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4 years ago

3(4h⁵ - k⁴) - (5h⁵ + 2k⁴)

Mathematics

1 answer:

SpyIntel [72]4 years ago

7 0

Answer:

The full answer is in the media.Good luck!

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2. The number of phones (landline and cell) owned by the members of each of nine families is 3, 5, 6, 6, 6,

kap26 [50]

Answer:

mean = 6

Step-by-step explanation:

hope this help you !! ;))

8 0

3 years ago

Use the quadratic formula to solve for x.

ivann1987 [24]

Answer:

x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3

Step-by-step explanation:

Solve for x:

6 x^2 - 4 x = 1

Divide both sides by 6:

x^2 - (2 x)/3 = 1/6

Add 1/9 to both sides:

x^2 - (2 x)/3 + 1/9 = 5/18

Write the left hand side as a square:

(x - 1/3)^2 = 5/18

Take the square root of both sides:

x - 1/3 = sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3

Add 1/3 to both sides:

x = 1/3 + sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3

Add 1/3 to both sides:

Answer: x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3

5 0

3 years ago

What is x in the equation 4x - 12 equals -7x - 111

lukranit [14]

4x - 12 = -7x - 111
11x = -99
x = -9

5 0

3 years ago

Read 2 more answers

Barrett works at an ice cream shop. The function f(x) represents the amount of money in dollars Barrett earns per gallon of ice

Paha777 [63]

Answer:

$f(g(x))=6x^3} +4$

Step-by-step explanation:

Given:

$f(x)=2x^2+4\\\\g(x)=\sqrt{3x^3}$

Required:

f(g(x))=?

Solution:

let f(g(x))=f(X), where X=g(x)

so $f(X)=2X^2+4$

put X= $g(x)=\sqrt{3x^3}$ , we get

$f(g(x))=2(\sqrt{3x^3} )^2+4$

$f(g(x))=2(\sqrt{3x^3} )^2+4\\\\f(g(x))=2({3x^3} )+4\\\\f(g(x))=6x^3} +4$

5 0

3 years ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

3 years ago