Taking commen 2 in RHS
p = 2 (L+W )
Divide by 2 on both sides.
p/2 = L+W
Subtract W on both sides.
p/2 - W = L
or L = p/2- W
HOPE IT HELPS YOU
Solve for x.
1 answer:
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Taking commen 2 in RHS
p = 2 (L+W )
Divide by 2 on both sides.
p/2 = L+W
Subtract W on both sides.
p/2 - W = L
or L = p/2- W
HOPE IT HELPS YOU
Computing the rate we get:
Then, when the assembly line runs at the same rate for 24 hours they will produce:
Answer: Option C) 720.
Answer: Area of cross section that is parallel to face CDHG is 432 cm².
Step-by-step explanation:
Since we have given that
There is a cross section that is parallel to face CDHG.
So, Length of cross section would be 36 cm
Width of cross section would be 12 cm.
So, Area of cross section would be
Hence, Area of cross section that is parallel to face CDHG is 432 cm².
Let us suppose that 'm' cookies and 'n' brownies were baked.
Since, Helen baked 31 items in total.
So, m+n = 31 (Equaion 1)
So, m = 31-n
Now, since cookies are sold for 95 cents, and the brownies sold for 60 cents.
Since, 1 $ = 100 cents
So, cookies are sold for $0.95, and the brownies sold for $0.60.
Helen sold the cookies and brownies at $23.85
So, 0.95m + 0.60n = 23.85 (Equaion 2)
Substituting the value of 'm' in equation 2, we get as
29.45 - 0.95n +0.60n = 23.85
-0.35n = -5.6
So, n = 16
Since, m = 31-n
m = 31-16
m = 15
So, Helen sold 15 cookies and 16 brownies.