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Aneli [31]
3 years ago
11

(100 Points and Brainlest)

Mathematics
2 answers:
lara31 [8.8K]3 years ago
7 0

1.    The graph is hard to read.  I would say about 4.3

2.  It is very close to the same number 4.5

3.  The 19-24 age group has the lowest number of wrecks in December

4.Teenagers and early 20's is the intended audience to show them the number or accidents caused by distracted driving by people of their age.

MrRa [10]3 years ago
4 0

1. The graph is hard to read.  I would say about 4.3

2. It is very close to the same number 4.5

3. The 19-24 age group has the lowest number of wrecks in December

4. Teenagers and early '20s is the intended audience to show them the number of accidents caused by distracted driving by people of their age.

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The marine green turtle has been known to swim 480 km (300 miles) in 10 days." How far, in kilometers, could a marine green turt
AnnyKZ [126]

Answer:

864

Step-by-step explanation:

You need to divide 480 by 10. Then multiply the answer which is 48 miles per day. Then take the 48 times 8 for the next 8 days. Then add the answer of that which is 384 and add it to 480.

Hope this helps.

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3 years ago
Please please help !!! will give brainliest to first correct answer
Oksi-84 [34.3K]

Answer:

[See Below]

Step-by-step explanation:

❶ It is irrational because to make it repeating it must be <u>EXACT</u>. In this case it is adding a 0 after every 1. So it'd be irrational since it doesn't have an end.

❷ Irrational because no one knows the end of pi. It doesn't have an ending so therefore irrational.

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3 years ago
What is the surface area for this?
DanielleElmas [232]

It is 6 sq. units. I hope you do well. Have a wonderful day.

6 0
2 years ago
If you answer this correctly I’ll give you brianslt
TEA [102]

Answer:

Step-by-step explanation:

6,0 would be your coordinates

2,4

6,12

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7 0
2 years ago
Read 2 more answers
Let f(x)=5x3−60x+5 input the interval(s) on which f is increasing. (-inf,-2)u(2,inf) input the interval(s) on which f is decreas
o-na [289]
Answers:

(a) f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing at (-2,2).

(c) f is concave up at (2, \infty)

(d) f is concave down at (-\infty, 2)

Explanations:

(a) f is increasing when the derivative is positive. So, we find values of x such that the derivative is positive. Note that

f'(x) = 15x^2 - 60&#10;

So,

&#10;f'(x) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 15x^2 - 60 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 15(x - 2)(x + 2) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textgreater \  0} \text{   (1)}

The zeroes of (x - 2)(x + 2) are 2 and -2. So we can obtain sign of (x - 2)(x + 2) by considering the following possible values of x:

-->> x < -2
-->> -2 < x < 2
--->> x > 2

If x < -2, then (x - 2) and (x + 2) are both negative. Thus, (x - 2)(x + 2) > 0.

If -2 < x < 2, then x + 2 is positive but x - 2 is negative. So, (x - 2)(x + 2) < 0.
 If x > 2, then (x - 2) and (x + 2) are both positive. Thus, (x - 2)(x + 2) > 0.

So, (x - 2)(x + 2) is positive when x < -2 or x > 2. Since

f'(x) \ \textgreater \  0 \Leftrightarrow (x - 2)(x + 2)  \ \textgreater \  0

Thus, f'(x) > 0 only when x < -2 or x > 2. Hence f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing only when the derivative of f is negative. Since

f'(x) = 15x^2 - 60

Using the similar computation in (a), 

f'(x) \ \textless \  \ 0 \\ \\ \Leftrightarrow 15x^2 - 60 \ \textless \  0 \\ \\ \Leftrightarrow 15(x - 2)(x + 2) \ \ \textless \  0 \\ \\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textless \  0} \text{ (2)}

Based on the computation in (a), (x - 2)(x + 2) < 0 only when -2 < x < 2.

Thus, f'(x) < 0 if and only if -2 < x < 2. Hence f is decreasing at (-2, 2)

(c) f is concave up if and only if the second derivative of f is positive. Note that

f''(x) = 30x - 60

Since,

f''(x) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30x - 60 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30(x - 2) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow x - 2 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow \boxed{x \ \textgreater \  2}

Therefore, f is concave up at (2, \infty).

(d) Note that f is concave down if and only if the second derivative of f is negative. Since,

f''(x) = 30x - 60

Using the similar computation in (c), 

f''(x) \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30x - 60 \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30(x - 2) \ \textless \  0 &#10;\\ \\ \Leftrightarrow x - 2 \ \textless \  0 &#10;\\ \\ \Leftrightarrow \boxed{x \ \textless \  2}

Therefore, f is concave down at (-\infty, 2).
3 0
3 years ago
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