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KiRa [710]
3 years ago
6

Light travels at a speed of about 186,000 miles per second. How far does light travel in 5 second? Use repeated addition to solv

e.
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

Step-by-step explanation:

The speed of light in a vacuum is 186,282 miles per second (299,792 kilometres per second), and in theory nothing can travel faster than light. In miles per hour, light speed is, well, a lot: about 670,616,629 mph. If you could travel at the speed of light, you could go around the Earth 7.5 times in one second.

186 ,282 x 5  = 931 , 410  for 5 seconds

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The sum of 75ml plus 7ml
Andrews [41]
The answer is 82ml. You add 75 and 7.
5 0
3 years ago
Kate has an interior decorating business. She charges a base fee of $25 for each visit and $40 per hour for her labor. 1) Write
nataly862011 [7]

Answer:

1) C = $25 + $40 × h

2) The domain for the ≠unction is 0 ≤ h ≤ ∞

The range for the function is 25 ≤ C ≤ ∞

3) Continuous

Step-by-step explanation:

1) The given parameters are;

The base fee charged = $25

The amount charged for labor = $40/hour

The total cost for h number of hours is C = $25 + $40 × h

2) The domain for the ≠unction is 0 ≤ h ≤ ∞

The range for the function is 25 ≤ C ≤ ∞

3) The situation is continuous because the different input values of h can be infinite (from o to infinity)

3 0
3 years ago
15 is 9 than j what is j in this question
marysya [2.9K]

Answer:

6

Step-by-step explanation:

15 is 9 more hence you subtract 9 from15

Hope this helps

3 0
2 years ago
Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down
Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}

10C2*15C1=675

2. Choose 3 Comedies from the 10. This is calculated as:

10C3=\frac{10!}{3!(10-3)!}=120

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

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3 years ago
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Answer:

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12

Step-by-step explanation:

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