Answer:
g = 5
Step-by-step explanation:
Solve for g:
4 (g - 1) + 2 (g + 5) = 36
4 (g - 1) = 4 g - 4:
4 g - 4 + 2 (g + 5) = 36
2 (g + 5) = 2 g + 10:
2 g + 10 + 4 g - 4 = 36
Grouping like terms, 4 g + 2 g - 4 + 10 = (4 g + 2 g) + (-4 + 10):
(4 g + 2 g) + (-4 + 10) = 36
4 g + 2 g = 6 g:
6 g + (-4 + 10) = 36
10 - 4 = 6:
6 g + 6 = 36
Subtract 6 from both sides:
6 g + (6 - 6) = 36 - 6
6 - 6 = 0:
6 g = 36 - 6
36 - 6 = 30:
6 g = 30
Divide both sides of 6 g = 30 by 6:
(6 g)/6 = 30/6
6/6 = 1:
g = 30/6
The gcd of 30 and 6 is 6, so 30/6 = (6×5)/(6×1) = 6/6×5 = 5:
Answer: g = 5
Answer:
35
Step-by-step explanation:
ok let's look at these old farts.
alvin is 8 years older than elga, so elga needs 8 more years to be as old as Alvin is. AKA,
Alvin = Elga + 8
The sum of their ages is 78.
Alvin + Elga = 78
Now put the equations together,
(Elga + 8) + Elga = 78
2 * Elga = 70
Elga = 35
Therefore, Elga is 35 years old! So old !!
Answer:
2,57 * 10^5 or 257000
Step-by-step explanation:
(5,14 * 10^9) / (2 * 10^4) =
2,57 * 10^5 =
257000
Answer:
Step-by-step explanation:Area = 1/2(b1 + b2)x h
Area = 18,000 ft^2
b1 = 80 ft
b2 = 100 ft
18,000 = 1/2(80 + 100) x h
36,000 = (180)h
h = 36,000/180
h = 200ft.
This is the distance between streets.
Hope this helps :-)Area = 1/2(b1 + b2)x h
Area = 18,000 ft^2
b1 = 80 ft
b2 = 100 ft
18,000 = 1/2(80 + 100) x h
36,000 = (180)h
h = 36,000/180
h = 200ft.
This is the distance between streets.
Hope this helps :-)
Answer:
x=2i, -2i
Step-by-step explanation:
