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Firdavs [7]
3 years ago
9

Secants ⎯⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ intersect in the exterior of a circle. DJH measures 191° and EG measures 53°. Determine the mea

sure of ∠ EFG.

Mathematics
1 answer:
Alik [6]3 years ago
4 0

Answer:

m\angle EFG =69\degree

Step-by-step explanation:

m\angle EFG =\frac{1}{2}(191- 53)\degree

m\angle EFG =\frac{1}{2}\times 138\degree

m\angle EFG =69\degree

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I need help please and thank you
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Answer:

2.72 x 10^4

Step-by-step explanation:

2.4 x 10^4

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= 24000 + 3200

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Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?
NISA [10]

An angle bisector divides an angle into two equal halves.

The measure of angle \angle CPD is 70 degrees

The complete question is an illustrates the concept of angle bisector;

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Because line PC bisects \angle RPD, then it means that the measure of RPD is twice the measure of CPD:

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