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3 years ago

What is the projection of (4,4) onto (-7,3)?

1 answer:

3 0

Let's define the vectors:
u = (4,4)
v = (- 7.3)
The projection of u on v is:
P = ((u.v) / (v ^ 2)) v
We have then:
u.v = (4,4). (- 7.3)
u.v = (4) * (- 7) + (4) * (3) = -28 + 12 = -16
v ^ 2 = (- 7) ^ 2 + (3) ^ 2 = 49 + 9 = 58
Substituting we have:
P = ((- 16) / (58)) (- 7, 3)
Rewriting:
P = -0.28 (-7, 3)
Answer:
the projection of (4,4) onto (-7,3) is:
C) -0.28 (-7.3)

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PLEASE HELP ASAP!!!!!!!

maria [59]

Answer:

40 cm² = B

178,127514 ≈ LA

218,127514 ≈ SA

Step-by-step explanation:

First and foremost, since we were not given a height, to find the height, take one-third of the area base [area base in this case is ws, since it is a rectangular base]: $\frac{1}{3}(40) = 13 \frac{1}{3}$

This is your height.

Now, to find the lateral area, we use this formula:

$l \sqrt{(\frac{w}{2})^{2} + {h}^{2}} + w \sqrt{( \frac{l}{2})^{2} + {h}^{2}} = L. A.$

Plugging these numbers into this formula will give you an approximate value of 178,127514.

Then you add the lateral area to the base area to get your surface area:

$40 + 178,127514 = 218,127514$

I am joyous to assist you anytime.

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3 years ago

The volume of a sphere is 972 PI ft3. What is the radius of the sphere? Use the formula V = 4/3 PI r3 to find your answer. Enter

Kryger [21]

972=4/3πr^3
729=πr^3
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4 years ago

Read 2 more answers

A pan of warm water (46∘ Celsius) was put in a refrigerator. After 15 minutes, the water's temperature was 27∘ C; 15 minutes aft

Cloud [144]

Answer:

The refrigerator was at around 13 ∘C

Step-by-step explanation:

Newton's Law of Cooling:

The rate of change of a body temperature (amount of heat loss/time of loss) is directly proportional to the difference between its own temperature and the surroundings.

$\frac{T(t2)-T(t1)}{t2-t1} = -h (T(t2) - Tenv)$

T ⇒ temperature

t ⇒ time

Tenv ⇒refrigerator temperature

$\frac{T(t2)-T(t1)}{t2-t1}$ ⇒ rate of change of he temperature

-h ⇒ constant of proportionality (negative because the temperature is decreasing inside the refrigerator)

We have 3 points:

time (minutes) - Temperature (∘ C)

0 (when the pan was put in the refrigerator) - 46

15 (after 15 minutes) - 27

30 (15 minutes after the first 15 minutes) - 19

$\frac{27 - 46}{15 - 0}$ = -h (27 - Tenv)

$\frac{19 - 27}{15 - 0}$ = -h (19 - Tenv)

Now we have a system of two equations and two variables

$\frac{-19}{15} = -h (27 - Tenv)\\ \frac{19}{15} = h (27 - Tenv)\\ \frac{19}{15(27 - Tenv)} = h$

$\frac{19 - 27}{15 - 0} = -h (19 - Tenv)\\\frac{-8}{15} = -h (19 - Tenv)\\\frac{8}{15} = h (19 - Tenv)\\\frac{8}{15} = \frac{19}{15(27 - Tenv)} (19 - Tenv)\\8(27 - Tenv) = 19 (19 - Tenv)\\216 - 8 Tenv = 361 - 19 Tenv\\19 Tenv - 8 Tenv = 361 - 216\\11 Tenv = 145 \\Tenv = 145/ 11\\Tenv = 13. 18$

The refrigerator was at around 13 ∘C

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3 years ago

find the square root of each of the following decimal numbers correct to two places of decimal : I. 175.01 II. 423.74 III. 5893.

netineya [11]

Answer:

i. 13.23

ii. 20.58

iii. 76.77

iv. 84.48

Step-by-step explanation:

Here , we are to calculate the square root of we have of the decimal numbers and correct to two decimal places.

i. √(175.01) = 13.229 = 13.23

ii. √(423.74) = 20.5849 = 20.58

iii. √(5893.27) = 76.767 = 76.77

iv. √(7136.8) = 84.4795 = 84.48

Kindly note that the approximation to two decimal places are the figures after the equal to

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A machine in a deli cooks hot dogs by rotating them past a heat sourse .one rotation takes 0.75 minutes and it takes 9 minutes t

Virty [35]

I believe it would be 12 because 9 min divided by .75 a rotation gets 12 rotations

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3 years ago