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2 years ago

Write the formula for the following sequence.5.8, 3.6, 1.4,...PLEASE SHOW YOUR WORK.

Mathematics

1 answer:

sladkih [1.3K]2 years ago

3 0

$tn = t(n - 1)- 2.2$

common difference is

3.6 - 5.8 = -2.2

let T1 = 5.8

T2 = 3.6

assuming we are to find T2

T2 = T(2-1) -2.2

= T1 -22

= 5.8 -2.2

= 3.6

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mr Goodwill [35]

Answer:

Step-by-step explanation:

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3 years ago

Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.

melamori03 [73]

Answer:

a) 0.8413

b) 421

c) $P_{95} = 189.675$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(IQ scores at most 180)

P(x < 180)

$P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)$

Calculation the value from standard normal z table, we have,

$P(x < 180) = 0.8413 = 84.13\%$

b) Number of the members of the club have IQ scores at most 180

n = 500

$\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421$

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

$P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95$

Calculation the value from standard normal z table, we have,

$P(z < 1.645) = 0.95$

$\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675$

$P_{95} = 189.675$

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3 years ago

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2 years ago

Write the formula for the following sequence.5.8, 3.6, 1.4,...PLEASE SHOW YOUR WORK.​

Write the formula for the following sequence.5.8, 3.6, 1.4,...PLEASE SHOW YOUR WORK.