Answer:
Week 4, 1400
Brainliest plz
Step-by-step explanation:
Answer:
A 2.5 × 10^–7 m
Step-by-step explanation:
Given
wavelength of violet light = 4.0 x 10^−7 m.
The wavelength of red light = 6.5 x 10^−7 m
To find the how much longer is wavelength of red light than violet light we have to find difference of wavelength of red and violet light
Difference in wavelength of red light and violet light =
wavelength of red light -wavelength of violet light
= 6.5 x 10^−7 m - 4.0 x 10^−7 m
Difference in wavelength of red light and violet light = (6.5 - 4.0)*10^−7 m
Difference in wavelength of red light and violet light =2.5 x 10^−7 m
Thus,
wavelength of red light is 2.5 x 10^−7 m longer than wavelength of violet light
option A
Given:
Total number of questions = 6
Choice for each question (in MCQ) = 4
Assuming that no questions are left unanswered.
To find:
The total number ways to answer the quiz, assuming that no questions are left unanswered.
Solution:
Here, Number of ways to answer each question = 4
To find the total number ways to answer 6 MCQ, we have to have to multiply number of ways to answer each question 6 times.
Total number of ways to answer six-question quiz with 4-choice multiple choice questions is

Therefore, the required number of ways is 4096.
Answer:
10 ounces of milk and 50 ounces of orange juice
Step-by-step explanation:
Let the amount of milk be x ounces and the amount of orange juice be y ounces.
1. An ounce of milk contains 20 milligrams of calcium and 60 micrograms of vitamin A. Then x ounces of milk contain 20x milligrams of calcium and 60x micrograms of vitamin A.
2. An ounce of orange juice contains 40 milligrams of calcium and 10 micrograms of vitamin A. Then y ounces of orange juice contain 40y milligrams of calcium and 10y micrograms of vitamin A.
<u>Calcium:</u>
20x milligrams in milk
40y milligrams in orange juice
2,200 milligrams in total
Hence,

<u>Vitamin A:</u>
60x micrograms in milk
10y micrograms in orange juice
1,100 micrograms in total
Hence,

Solve the system of two equations:

Divide each equation by 10:

From the second equation:

Substitute it into the first equation:
