All categories

4 years ago

Solve this quadratic equation using the quadratic formula. 5 - 10x - 3x2 = 0

Mathematics

1 answer:

mario62 [17]4 years ago

5 0

Answer:

Step-by-step explanation:

I have enclosed a picture of the quadratic formula because I cannot seem to write the proper formula since it wont let me

✯Hello✯

↪ Alright so first we need to work out values for A B AND C

↪ We need to rearrange this since its the wrong way around

↪ A = -3

B= -10

C= 5

↪ we substitute these values and we get x=0.44 and x=-3.78

❤Gianna❤

You might be interested in

Amy is eight years older than twice her cousin Alicia’s age. The sum of their ages is less than 32. Let x represent Alicia's age

Vladimir [108]

Assume that the age of Alicia is x and that of Amy is y
Twice the age of Alicia = 27
Eight years older means we will add 8
Therefore, the statement "Amy is eight years older than twice her cousin Alicia’s age" can be represented as follows:
y = 8 + 2x (equation)
The sum of their ages is less than 32 can be represented as:
x + y < 32 which can also be written as y < 32-x (inequality)

7 0

3 years ago

I need help to do equations into word probloems

guapka [62]

Answer:

use the equations that are given along with a little imagination.

Step-by-step explanation:

when turning equations into word problems you must use equation that's given.

For example:

•x -3=10

Now lead them into the problem:

-Lyndsey bought 3 less shirts than Riley. Solve for x, How many shirts does Riley have more than Lyndsey if together they have 10 shirts?

5 0

4 years ago

B) Write 25 x 10° in standard form.

xz_007 [3.2K]

25 anything raised to zero equals one

3 0

3 years ago

Find the volume of this square pyramid to the nearest tenth. 16 cm 7 cm

V125BC [204]

Answer:

16 cm

Step-by-step explanation:

3 0

3 years ago

1. A MAP SCALE READS 1CM:5KM. IF A DISTANCE ON THE MAP MEASURES 7CM, THE ACTUAL DISTANCE WILL BE?. 2. A SCHOOL DINING HALL IS 35

Agata [3.3K]

Answer:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. $42^\circ$

5. 16.73 m

Step-by-step explanation:

Solution 1.

Reading of map scale = 1cm:5km

i.e. 1 cm is equivalent to 5 km

Measurement of map = 7 cm

Actual distance = Measurement of map $\times 5$

Actual distance = 7 $\times 5$ = 35 km

-------------------

Solution 2.

Length of dining hall = 35 m

Measurement of map = 7 cm

Scale = Measurement of map : Length of dining hall (i.e. ratio)

Scale = 7 cm :35 m = 1 cm : 5 m

-------------------

Solution 3.

Length of building = 30 m

Scale = 1 cm to 5m

5 m is equivalent to 1 cm on scale

1 m is equivalent to $\frac{1}{5}$ cm on scale

30m is equivalent to $\frac{1}{5} \times 30$ = 6 cm on scale

-------------------

Solution 4.

Angle of elevation of A from B = $42^\circ$

Angle of depression of B from A = ?

Please refer to the image attached, we can clearly observe that both the angles (i.e. angle of elevation from A to B and angle of depression from B to A )will be equal.

Angle of depression of B from A = $42^\circ$

-------------------

Solution 5.

Given that:

String length, or hypotenuse of triangle BC= 25 m

Angle of string with horizontal, $\angle B = 42^\circ$

Please refer to the attached image for the clear understanding of the situation.

To find:

Height, AC = ?

We can use trigonometric identity:

$sin\theta = \dfrac{Perpendicular}{Hypotenuse}$

$sinB = \dfrac{AC}{BC}\\\Rightarrow sin42^\circ = \dfrac{AC}{25}\\\Rightarrow AC = 25 \times 0.67\\\Rightarrow AC = 16.73 m$

============

So, the answers are:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. $42^\circ$

5. 16.73 m

7 0

3 years ago