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algol [13]
4 years ago
9

If y ≠ 1, is x = 1 ? (1) x2 + y2 = 1 (2) y = 1 – x Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. EACH statement ALONE is sufficient. Statements (1) and (2) TOGETHER are NOT sufficient.
Mathematics
1 answer:
stiv31 [10]4 years ago
3 0

Answer:

Statements (1) and (2) TOGETHER are NOT sufficient.

Step-by-step explanation:

If y ≠ 1, is x = 1 ?

(1) x^2+y^2 = 1

(2) y = 1 – x

The two statements are not sufficient to assert this claim. The statement If y ≠ 1, is x = 1 only holds in the two statements if y=0 as seen below.

(1) x^2+y^2 = 1

x^2+0^2=1

x=1

(2) y = 1 – x

0=1-x

x=1

Every other value of y fails the condition. So a sufficient statement would have been:

If y ≠ 1, and y=0, is x = 1 ?

(1) x^2+y^2 = 1

(2) y = 1 – x

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The answer can be found with the knowledge that the area of a triangle is half of the height * width. You know the width of ∠BAC is 4, and the area is 8, so 16 (the area doubled) / 4 is the height. The width and height of ∠BAC are the same, and since the proportions are also the same, the width and height of ∠EDF are both 3. So the area is the width (3) times the height (3) divided by 2.

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