How many square inches are 9 cubes with a 1 inch edge

URGENT!! Solve the following for θ, in radians, where 0≤θ<2π.

lidiya [134]

Answer: 0.93 radians & 2.21 radians

Step-by-step explanation:

$-4sin^2\theta-3sin\theta+5=0\\\\\text{Since this is not factorable, use the quadratic formula to find the roots:}\\\\sin\theta=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(-4)(5)}}{2(-4)}\\\\\\.\quad=\dfrac{3\pm \sqrt{9+80}}{-8}\\\\\\.\quad=\dfrac{3\pm\sqrt{89}}{-8}\\\\\\.\quad=\dfrac{3\pm9.43}{-8}\\\\\\.\quad=\dfrac{12.43}{-8}\quad and\quad \dfrac{-6.43}{-8}\\\\\\.\quad=-1.55\quad and\quad 0.80\\\\\\\theta=sin^{-1}(-1.55)\quad and\quad \theta=sin^{-1}(0.80)$

$\theta=not\ valid\qquad and\quad \theta=0.927$

$\theta = 0.927\ radians\text{\ in the 1st quadrant and}\\\pi-0.927=2.21\ radians\text{\ in the 2nd quadrant}$

6 0

4 years ago

Read 2 more answers

Rewrite the expression with rational exponents as a radical expression by extending the properties of integer exponents. two to

Lubov Fominskaja [6]

Answer:

The answer is " $\sqrt[8]{2^5}$ ".

Step-by-step explanation:

Given value:

$\to \frac{2 \frac{7}{8}}{2 \frac{1}{4}}$

They understand that, by using algebraic expressions laws, they subtract that inverse whenever we subtract powers with the same base. Every exponent's core is 2, therefore we subtract:

$\to \frac{7}{8} - \frac{1}{4}$

They have a shared denominator. It's least that is equally divided

among 8 or 2 is 8:

$\to \frac{7}{8} - \frac{2}{8}\\$

$\to \frac{7-2}{8}\\\\\to \frac{5}{8}\\\\$

This gives us:

$\to 2 \frac{5}{8}$

As rational notation is written as extremists, that root was its denominator as well as the power seems to be the numerator.

Which means 8 is the root and 5 the force that gives us:

$\sqrt[8]{2^5}$

7 0

3 years ago

Write an equation for the line shown on the graph.

Irina18 [472]

Answer:

$\large\boxed{y=\dfrac{2}{3}x+1}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

The fromual of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

(x₁, y₁), (x₂, y₂) - points on a line

We have the points from the graph:

(0, 1) → b = 1 and (3, 3).

Calculate the slope:

$m=\dfrac{3-1}{3-0}=\dfrac{2}{3}$

Finally we have the equation of a line:

$y=\dfrac{2}{3}x+1$

3 0

3 years ago

Explain why it's sometimes helpful to use the point-slope form instead of the slope-intercept form..

Firdavs [7]

For a slope-intercept form, you only have the data of the slope and the y-intercept. On the other hand, for a point-slope form, you have data on the slope and one point. It is sometimes useful to make use of the latter because in this form, you can graph the equation using only one point. You can also see a point included on the line.

4 0

4 years ago

Check all the true statements.

andrew-mc [135]

Answer:

The true statements are:

2DE = AC

1/2AC = DE

DE || AC

Step-by-step explanation:

As we are given,

AD = 3.5 and BD = 3.5

CE = 3 and BE = 3

From the given triangle ΔABC, it is clear that:

The segment DE bisects the sides AB and BC, so

AD = BD

CE = BE

It is clear that the segment DE is parallel to the segment AC, thus

DE || AC

As DE is the midsegment between AB and BC, so

2DE = AC

1/2AC = DE

Thus, the true statements are:

2DE = AC

1/2AC = DE

DE || AC

5 0

3 years ago