By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1 b) p≤1/2 c) s>-1.
I found the complete question on Chegg, here is the full question:
Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1) b) g(p)=√(1-2p) c) m(s)= (s^2+4s+4)/√(s+1)
Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.
a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.
b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.
c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.
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Answer: me too
Step-by-step explanation: me + bore = suffer
but,
me + life = suffer - me
= suffer = 0
have a good one
So you find out how many triangles are in this by taking a point and making a line to another point that isn't on the same line. this one has 3 triangles. each triangle is 180*(using multiplication symbol for degree symbol).you do this to find out what the number of angles adds up to. 180* multiplied by 3 equals 540*. Then if you add up all the angles you have 400*. 540 - 400 equals 140*. So the final angle is 140*. Hope this helps!
Answer:
<h3>
P(-5, -1)</h3>
Step-by-step explanation:
If M is midpoint of AP then:
The least common multiple of these two numbers is 2310. Hope this helps
