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expeople1 [14]
3 years ago
12

If Ms. P wants to withdraw $900 from an account earning 4% average annual interest rate at the start of each year for 7 years, h

ow much must she have in the account today?
Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

Amount he must have in his account today is  $5,617.92

Step-by-step explanation:

Data provided in the question:

Regular withdraw amount = $900

Average annual interest rate, i = 4% = 0.04

Time, n = 7 years

Now,

Present Value = C \times\left[ \frac{1-(1+i)^{-n}}{i} \right] \times(1 + i)

here,

C = Regular withdraw amount

Thus,

Present Value = C \times\left[ \frac{1-(1+i)^{-n}}{i} \right] \times(1 + i)

Present Value = 900 \times\left[ \frac{1-(1+0.04)^{-7}}{ 0.04 } \right] \times(1 + 0.04)

Present Value = 936 \times\left[ \frac{1 - 1.04^{-7}}{ 0.04} \right]

Present Value = 936 \times\left[ \frac{1 - 0.759918}{ 0.04} \right]

Present Value = 936 × 6.00205

or

Present Value = $5,617.92

Hence,

Amount he must have in his account today is  $5,617.92

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Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug
gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems  

In C(5,3)=10ways, this can be achieved  

In part a:

Space sample chooses 3 of a 5 systems  

(M_1, \ M_2,\ M_3),(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort  

Outcomes probable =

(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6

\to p(A)=\frac{6}{10}\\\\

            =0.6

In point c:

B = highest effort that is M_5

Potential result=

(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6  \\\\

\to B= \frac{6}{10} \\\\

        =0.6

\to P(B)=10

In point d:

\to \ A  \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)

\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \

                                      =0.3

In point e:

\to (A \cup B) =  (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9\to P(A \cap B)=\frac{9}{10}

                    = 0.9

In point f:

\to (A\cap B) = \frac{3}{10}

                 = 0.3

In point g:

\to (A \cup B) = \frac{7}{10}

                 =0.7

In point h:

\to p(A \cap B) = 0.3 \neq 0

8 0
3 years ago
Hi can anyone help me please???? thank you!
SCORPION-xisa [38]
The answer is C, because t shows time when you plug in a number for t the output will be the distance walked in that time. the first 0.5 hours (aka D(0.5) ) he walked is less than the second 0.5 (aka D(1) - D(0.5) ).
3 0
3 years ago
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Obtaining a measure of intelligence from a group of college students would likely yield a somewhat normal distribution (that is,
ki77a [65]

Answer:

C. Mean

Step-by-step explanation:

We have been given that obtaining a measure of intelligence from a group of college students would likely yield a somewhat normal distribution (that is, there shouldn't be any extreme outliers).

We know that median is best measure of central tendency with extreme outliers, while mean is the best measure of central tendency when the data is normally distributed.

Mode is used when data are measured in a nominal scale.

Since the measure of intelligence from a group of college students yield a somewhat normal distribution, therefore, mean will be the best measure of central tendency.  

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Alexis wants to make a paperweight at pottery class. He designs a pyramid-like model with a base area of 100 square centimeters
grigory [225]

Answer:

The density of the material must be at least 1.5 g/cm³.

Step-by-step explanation:

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3 years ago
A total of $12,000 is invested at an annual interest rate of 9%. Find the balance
sineoko [7]

Answer:

$18,726.11

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First lets change 9% into a decimal:

9% -> \frac{9}{100} -> 0.09

Since the interest is compounded quarterly, we will use 4 for n. Lets plug in the values now:

A=12,000(1+\frac{0.09}{4})^{4(5)}

A=18,726.11

<u>The balance after 5 years is $18,726.11</u>

6 0
3 years ago
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