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cupoosta [38]
3 years ago
11

A box of matching game pieces contains 8 red pieces, 5 green pieces, and 7 yellow pieces. You reach in and randomly take out one

piece and then a second piece. Find the probability of drawing a green piece followed by a red piece.
A) 10/39
B) 1/10
C) 2/19
D) 7/76
Mathematics
2 answers:
klemol [59]3 years ago
8 0

Answer:

The correct answer is C) \frac{2}{19}

Step-by-step explanation:

Step 1

We start by breaking up the process into 2 parts. The first part of the process is finding the probability of selecting a green piece out of 20 pieces. Since there are 5 green pieces, this probability is \frac{5}{20}

Step 2

The second part of this process is that of selecting a red piece out of 19 pieces since the first piece was not replaced. If the first piece was green, taken without replacement, there are now 8 red pieces out of 19 pieces in total

Step 3

The next step is t find the probability using the multiplication rule. To find the probability of finding green piece followed by a red piece we just multiply the probabilities from step 1 and 2.

The calculation for this process is shown below,

\frac{5}{20}\times  \frac{8}{19} 0\frac{40}{380} =\frac{2}{19}


Tanzania [10]3 years ago
3 0
It should  be B.
correct me if i'm wrong
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========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

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---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

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Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

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