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hichkok12 [17]
3 years ago
9

How do I solve this

Mathematics
1 answer:
ra1l [238]3 years ago
5 0
-2+(-5)=-7 and 6+(-3)=3
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The circumference of a flower garden is 247 ud. What is the area of the flower garden in terms of
lisov135 [29]

Answer:15252.25π^3

Step-by-step explanation:

Radius=r

Circumference=247 ud

Circumference=2 x π x r

247=2πr

Divide both sides by 2π

247/2π=2πr/2π

123.5π=r

Radius=123.5π

Area of circle=π x r x r

Area of circle=π x 123.5π x 123.5π

Area of circle=15252.25π^3

4 0
3 years ago
Does anyone know how to do this?
aksik [14]

Answer:

So basically the answer is where the lines intersect if they do not intersect there is no solution if they are on top of one another it is infinite solutions

Step-by-step explanation:

3 0
3 years ago
Name three radii of Circle S.
Talja [164]

Answer:

circle S radii SU, ST, SR

Circle U radii UT, US, UR

Step-by-step explanation:

Radii start in the middle of the circle to the end of the circle.

5 0
3 years ago
Read 2 more answers
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
Help PLEASE THE LINK IS DOWN BELOW I TIMES
Mamont248 [21]
The answer is A because its simple reading. Are you 4? Because this is easy smh
3 0
3 years ago
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