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4 years ago

12

I need help with this

1 answer:

Genrish500 [490]4 years ago

4 0

Answer:

Step-by-step explanation:

Angle QPR is a central angle. When a central angle intercepts an arc of a circle, the arc and the angle have the same measure. So the minor arc, the one that is less than 180 degrees, will have the same measure as the central angle, 170 degrees.

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Round your answer to the nearest hundredth.<br> -1.7f - 26 = 34

Softa [21]

F=-35.29
Add 26 to both sides. -1.7=34+26
Simply 34+26=60 -1.7f=60
Divide both sides by -1.7 f=-60/1.7
Simply-60/1.7 to get -35.294118 then round to nearest hundredth to get F=-35.29
Hope That helps!!!

6 0

3 years ago

Pls helpppp I don’t know how to do this

Pavel [41]

Answer is 53911

Step-by-step explanation:

Just multiply to get the answer

3 0

3 years ago

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Joyce is helping her aunt creat craft kits. Her aunt has 138 pipe cleaners, and each kit will include 6 pipe cleaners. What is t

Setler79 [48]

They put 138 into groups of 6, so divide 138 by 6.

138/6

23 craft kits.

Hope this helps! :D

8 0

4 years ago

Read 2 more answers

In 1932 the percentage of workers who had any form of employment-related pensions was about

ankoles [38]

The answer is 15% have a good day

3 0

3 years ago

Sand is leaking through a small hole at the bottom of a conical funnel at the rate of 12cm3/s . if the radius of the funnel is 8

Bezzdna [24]

Answer:

h ≅ 16.29 cm

$\mathbf{\dfrac{dh}{dt}= -0.1809 \ cm/s}$

Step-by-step explanation:

From the conical funnel;

Let the adjacent line at the base of the cone be radius (r) and the opposite ( vertical length) be the height (h)

Then;

$tan \theta= \dfrac{r}{h}$

$tan \theta= \dfrac{8}{16}$

$tan \theta= \dfrac{1}{2}$

∴

$\dfrac{r}{h} = \dfrac{1}{2}$

$r = \dfrac{h}{2}$

The volume (V) of the cone is expressed as:

$V = \dfrac{1}{3}\pi r ^2 h$

$V = \dfrac{1}{3}\pi (\dfrac{h}{2})^2 h$

$V = \dfrac{\pi h^3}{3\times 4}$

$\dfrac{dv}{dt} = \dfrac{3 \pi h^2}{3 \times 4} \dfrac{dh}{dt}$

$\dfrac{dv}{dt} = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}$

Given that:

$\dfrac{dv}{dt} = 12 \pi$

Then:

$-12 \pi = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}$

$- \int 48 \ dt = \int h^2 \ dh$

$\dfrac{h^3}{3}= -48 t + c$

$At \ t = 0 \ ; h = 0$

∴

$\dfrac{0^3}{3} = -48(0) + c$

c = 0

So;

$\dfrac{h^3}{3}= -48 t + 0$

$\dfrac{h^3}{3}= -48 t$

t = 30

$\implies h = (-48(30))^{1/3}$

h = 16.2865

h ≅ 16.29 cm

Thus;

from $-12 \pi = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}$

$\dfrac{-12 \pi} { \dfrac{ \pi h^2}{4} } =\dfrac{dh}{dt}$

$\dfrac{dh}{dt} = \dfrac{-12 \pi} { \dfrac{ \pi h^2}{4} }$

$\dfrac{dh}{dt}=\dfrac{-12 \times 4} { {16.29^2} }$

$\mathbf{\dfrac{dh}{dt}= -0.1809 \ cm/s}$

7 0

3 years ago