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QveST [7]
3 years ago
6

Hello I'm in 6th grade. And I need help. what is

e="3\frac{3}{4}" alt="3\frac{3}{4}" align="absmiddle" class="latex-formula"> times (-2\frac{4}{5} )?
Mathematics
1 answer:
Ghella [55]3 years ago
4 0

Answer:

-42/4 or -10 1/2

Step-by-step explanation:

So you might want to convert the mixed numbers to improper fractions.

15/4*(-14/5)

Then what you want to do is cross multiply.

Since 5 can go into 15 that would make it into..

3/4*(14/1)

which makes it way easier to multiply.

3*(-14)= -42

4*(-1)= -4

your answer would be

-42/4 or -10 1/2

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Tripp and Rico are two dogs. Tripp weighs exactly 35 pounds more than Rico. Together, they weigh exactly 49 pounds. How much doe
babymother [125]
Call the weights of the two dogs t and r.

We know that Tripp weights 35lbs more than Rico, or:
t=r+35

We also know that the total weight of both dogs is 49lbs.:
t+r=49

Now, by substitution:
(r+35)+r=49
2r+35=49
2r+35-35=49-35
2r=14
r=\frac{14}{2}
r=7
Rico weighs 7lbs.

Then:
t=r+35
t=7+35
t=42
Tripp weighs 42lbs.

To check our work:
t+r=49
42+7=49
49=49  CHECK!
5 0
3 years ago
Find x and y when bxby = b8 and b4xb-2y=b2​
Anika [276]

Answer:

x = 1/y

Step-by-step explanation:

6 0
3 years ago
in triangle ABC angle A is a right angle and m B=45. Find BC. If your answer is not an integer, leave it in the simplest radical
Sergio039 [100]
I believe it's \sqrt[12]{2}

Hope I helped! ( Smiles )
5 0
3 years ago
Help me Guess just help please
Andrew [12]

Answer:

maybe 2 only?

Step-by-step explanation:

I'm just guessing but it sounds right

7 0
3 years ago
Read 2 more answers
What is the approximate area of a circle with a radius of 10 in?
yKpoI14uk [10]

<em></em>\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}

<em></em>

<em>Correction to your question text: diameter, not radius.</em>

The area of a circle is given by:

A=\pi r^2

The radius is half of the diameter.

A=\pi\cdot\left(\dfrac{10}{2}\right)^2

Substitute and solve.

\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}

5 0
2 years ago
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