Question

A ray of light is incident at an angle of 56.2 ◦ on the surface of a piece of crown glass whose index of refraction is 1.52 . What is the angle of refraction? Answer in units of ◦ .

Answer 1

Answer:

$33^{\circ}$

Step-by-step explanation:

Angle of incidence is the angle formed at the point of incidence between the incident ray and the normal. Angle of refraction is the angle formed between the refracted ray and the normal .

According to Snell's law,

$n_i\,\sin \theta _i=n_r\,\sin \theta _r$

Here, $n_i,n_r$ are indexes of incidence and refraction.

$\sin \theta _i,\sin \theta _r$ are angles of incidence and refraction.

Given:

$n_i=1,n_r=1.52, \theta _i=56.2^{\circ}$

On putting these values in the Snell's law, we get

$n_i\,\sin \theta _i=n_r\,\sin \theta _r\\(1)\sin 56.2^{\circ}=1.52\sin \theta _r\\\frac{\sin 56.2^{\circ}}{1.52}=\sin \theta _r\\0.55=\sin \theta _r\\33^{\circ}=\theta _r$