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JulsSmile [24]
2 years ago
10

2x^3+4x^3 is the same as

Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer:

6x^3 is the answer

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Rewrite the equation for x, and express its value in terms of a. 3/a x - 4 = 20
My name is Ann [436]

For this case, we must clear variable "x" from the given equation, expressed in terms of "a".

We have:

3/a x-4=20

By clearing "x" we have:

Adding 4 to both sides of the equation:

3/a x = 20 + 4

Multiplying by a/3 on both sides of the equation:

x=24a/3

x=8a

So, x=8a

Answer:

x=8a

7 0
3 years ago
Find the value of 3u-8 given that -7u + 9=2
bulgar [2K]

Answer:

-5

Step-by-step explanation:

-7u+9=2

-7u=2-9

-7u=-7

7u=7

u=7/7

u=1

3(1)-8=3-8=-5

8 0
3 years ago
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What is the solution to 2x-8 <12?
rusak2 [61]

Answer:

x < 10

Step-by-step explanation:

2x - 8 < 12 \\ 2x - 8 + 8 < 12 + 8 \\( 2x < 20) \div 2 = x < 10

7 0
3 years ago
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Evaluate 2a - b for a = 2 and b = 3.
SVEN [57.7K]
2a - b....a = 2 and b = 3

2(2) - 3 = 
4 - 3 =
1
4 0
2 years ago
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Situation:
Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

<u>Given formula:</u>

\sf N=N_0e^{-kt}

  • \sf N_0 = initial mass (at time t=0)
  • N = mass (at time t)
  • k = a positive constant
  • t = time (in days)

Given values:

  • \sf N_0 = 11 g
  • k = 0.125

Half-life:  The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

5 0
1 year ago
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