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Mumz [18]
4 years ago
10

What are the domain and range for the cube root function graphed below?

Mathematics
2 answers:
Art [367]4 years ago
8 0
Both are real numbers.
Dmitrij [34]4 years ago
6 0
Easy just use desmos.com is not that hard hope this helps mark me as a brainiest!!!
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A palindrome is chosen at random from the list of all $6$-digit palindromes, with all entries equally likely to be chosen. (Reca
kirill115 [55]

Answer:

Expected value 550,000

Step-by-step explanation:

Calculation of the expected value of the chosen number

We should know that each of the digit of the number may likely be thought of what we called a random variable, in which the first digits and the last digits comes uniformly from [1,2,3,4,5,6,7,8,9] while the last digit can't be 0 because of what we called the palindrome condition).

Therefore each of these two digits will have an expected value of 5 while the other four digits will come uniformly from this digits which are [0,1,2,3,4,5,6,7,8,9] in which each of the digits will have an expected value of 4.5.

Thus Expected value is additive, which means we have to also take place the value into account.

Now let find the EXPECTED VALUE

The expected value will be :

(100,000+1)⋅(5)+(10,000+1,000+100+10)⋅(4.5)

Expected value=550,000

Therefore the Expected value will be 550,000

4 0
3 years ago
Need help with #5.<br> Find angle and solve for x
Leona [35]

Answer:

see explanation

Step-by-step explanation:

The 2 marked angles are vertical and congruent, thus

24x = 23x + 5 ( subtract 23x from both sides )

x = 5

Thus angles = 24 × 5 = 120°

6 0
3 years ago
A stock investment went up 25% in 2006. Starting at this increased value, what percent would it have to go down in 2007 to be ba
pentagon [3]
Is it -25%. I’m guessing. I’m not sure if that is correct.
3 0
3 years ago
Read 2 more answers
The sum of two numbers is 300 and the two numbers have a ratio of 20:10.find the larger number
Stolb23 [73]
The larger number is 200. The ratio is 20:10 and 200 + 100 = 300.
4 0
4 years ago
Read 2 more answers
Solve (D^3-D^2-D-2)y=0
allsm [11]

(^3-^2+2)D=0

D^2+D^2+2D=0

2D^2+2D=0

a = 2; b = 2; c = 0;

Δ = b2-4ac

Δ = 22-4·2·0

Δ = 4

D1=−b−Δ√2aD2=−b+Δ√2a

Δ−−√=4√=2

D1=−b−Δ√2a=−(2)−22∗2=−44=−1

D2=−b+Δ√2a=−(2)+22∗2=04=0

8 0
3 years ago
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