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zloy xaker [14]
3 years ago
6

Solve for x: -2x + 5 < 7

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
5 0
-2x+5<7
the answer is x > -1
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12
Tatiana [17]

Answer:

it 5.5⋅10−^8m

Step-by-step explanation:

Unless I'm missing something important here, you can find the difference between the two wavelengths by subtracting one from the other. Since you're interested in finding how much longer the wavelength associated with the orange light is, subtract the wavelength of the green light from the wavelength of the orange light. You know that the two measured wavelengths are 6.15 ⋅ 10 − 7 m → orange light 5.6 ⋅ 10 − 7 m → green light Therefore, the difference between the two wavelengths will be Δ wavelength = 6.15 ⋅ 10 − 7 m − 5.6 ⋅ 10 − 7 m = 5.5 ⋅ 10 − 8 m

3 0
3 years ago
Match each sine or cosine value to its equivalent measure.
Anastasy [175]

Answer:

the answer is C.

Step-by-step explanation:

if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8

there goes your answer.

3 0
2 years ago
The number of plants needed to fill a row in a farmer's field varies inversely as the distance between the plants. If 72 plants
Oliga [24]

Answer:

54.

Step-by-step explanation:

Cause plato.

5 0
3 years ago
The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50. He selects 4 of the 50 re
Mariana [72]

Answer:

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

Step-by-step explanation:

Sets are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Lots of 50 means that N = 50

5 are defective, which means that k = 5

4 are selected, which means that n = 4

Find the probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,50,4,5) = \frac{C_{5,2}*C_{45,2}}{C_{50,4}} = 0.0430

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

4 0
3 years ago
Can someone please help with these 2 questions? It would mean the world to me. I have attached the image for the questions.
sweet [91]

Answer:

2 \frac{1}{20}

Step-by-step explanation:

for question a)

It would be easier if you converted these to improper fractions (currently it is in the form of a proper fraction)

to convert to improper fraction, you would multiply the denominator (bottom no. of fraction) by the whole number , then add that with the numerator (top no. of fraction) and put the whole thing over the denominator.

E.g.

7 \frac{1}{4} = 7x4 + 1 = 29

Thus, improper fraction would be \frac{29}{4}

do same thing  for other one

thus , \frac{26}{5}

now,

\frac{29}{4} - \frac{26}{5}

however, you can't do this as the denominators are not the same, so multiply them by a number which would give the a common denominator (20 would be the best option for common denominator)

\frac{145}{20} -\frac{104}{20} = \frac{41}{20}

convert back to mixed number

2 \frac{1}{20}

5 0
3 years ago
Read 2 more answers
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