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Ilya [14]
3 years ago
11

Keegan makes a deposit into her savings account at the beginning of the year. The account earns 3% simple interest each year. Sh

e has $360.50 in her account at the end of the year. If Keegan did not make any additional deposits or withdrawals during the year, how much did she deposit into the account at the beginning of the year? $10.82 $277.31 $350.00 $371.32
Mathematics
2 answers:
Alinara [238K]3 years ago
7 0
She deposited $350.00 into the account at the beginning of the year.
mixas84 [53]3 years ago
4 0

Answer:  Keegan did a deposit of  $350.00 at the beginning of the year

Step-by-step explanation:

Hi, to solve this problem we have to analyze the information given:

  • Amount (A) : $360.50
  • Interest Rate (r): 3% = 0.03 (decimal)
  • Time(t)= 1 year

We have to apply the simple interest formula:

  • A = P(1 + rt)
  • 360.5= P (1+ 0.03x1 )

Now we have to calculate the value of the principal amount by solving the formula.

  • 360.5 = P (1.03)
  • 360.5/ 1.03 = P
  • P= 350

Keegan did a deposit of  $350.00 at the beginning of the year.

Feel free to ask for more if it´s necessary or if you did not understand something.

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ivanzaharov [21]
Its b !!!!!!!!!!!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
A piggy bank contains pennies, nickels, and dimes. The number of dimes is 15 more than the number of nickels, and there are 140
amm1812

Answer:

Option D is correct.

There are 34 nickels in the piggy bank.

Step-by-step explanation:

A piggy bank contains pennies, nickels and dimes.

Let the number of pennies be p

Let the number of nickels be n

Let the number of dimes be d

Also, note that 1 penny = $0.01

1 nickel = $0.05

1 dime = $0.10

- The number of dimes is 15 more than the number of nickels.

d = 15 + n

- There are 140 coins altogether totaling $7.17.

p + n + d = 140

0.01p + 0.05n + 0.1d = 7.17

Bringing the 3 equations together

d = 15 + n (eqn 1)

p + n + d = 140 (eqn 2)

0.01p + 0.05n + 0.1d = 7.17 (eqn 3)

Substitute (eqn 1) into (eqn 2)

p + n + d = 140

p + n + (15 + n) = 140

p + 2n + 15 = 140

p = 140 - 15 - 2n = 125 - 2n

p = 125 - 2n (eqn 4)

Substitute (eqn 1) and (eqn 4) into (eqn 3)

0.01p + 0.05n + 0.1d = 7.17

0.01(125 - 2n) + 0.05n + 0.1(15 + n) = 71.7

1.25 - 0.02n + 0.05n + 1.5 + 0.1n = 7.17

0.1n + 0.05n - 0.02n + 1.5 + 1.25 = 7.17

0.13n + 2.75 = 7.17

0.13n = 7.17 - 2.75 = 4.42

0.13n = 4.42

n = (4.42/0.13) = 34

d = 15 + n = 15 + 34 = 49

p = 125 -2n = 125 - (2×34) = 125 - 68 = 57

Hence, there are 57 pennies, 34 nickels and 49 dimes in the piggy bank.

Hope this Helps!!!

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3 years ago
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Answer:

\frac{49}{64}

Step-by-step explanation:

\frac{7}{8} * \frac{7}{8} = \frac{7*7}{8*8}= \frac{49}{64}

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