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Ilya [14]
3 years ago
11

Keegan makes a deposit into her savings account at the beginning of the year. The account earns 3% simple interest each year. Sh

e has $360.50 in her account at the end of the year. If Keegan did not make any additional deposits or withdrawals during the year, how much did she deposit into the account at the beginning of the year? $10.82 $277.31 $350.00 $371.32
Mathematics
2 answers:
Alinara [238K]3 years ago
7 0
She deposited $350.00 into the account at the beginning of the year.
mixas84 [53]3 years ago
4 0

Answer:  Keegan did a deposit of  $350.00 at the beginning of the year

Step-by-step explanation:

Hi, to solve this problem we have to analyze the information given:

  • Amount (A) : $360.50
  • Interest Rate (r): 3% = 0.03 (decimal)
  • Time(t)= 1 year

We have to apply the simple interest formula:

  • A = P(1 + rt)
  • 360.5= P (1+ 0.03x1 )

Now we have to calculate the value of the principal amount by solving the formula.

  • 360.5 = P (1.03)
  • 360.5/ 1.03 = P
  • P= 350

Keegan did a deposit of  $350.00 at the beginning of the year.

Feel free to ask for more if it´s necessary or if you did not understand something.

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Suppose that the distance, in miles, that people are willing to commute to work is an exponential random variable with a decay p
garik1379 [7]

Answer:

  • <em>m</em> = \frac{1}{20}
  • <em>μ</em> = 20
  • <em>σ </em>= 20

The probability that a person is willing to commute more than 25 miles is 0.2865.

Step-by-step explanation:

Exponential probability distribution is used to define the probability distribution of the amount of time until some specific event takes place.

A random variable <em>X</em> follows an exponential distribution with parameter <em>m</em>.

The decay parameter is, <em>m</em>.

The probability distribution function of an Exponential distribution is:

f(x)=me^{-mx}\ ;\ m>0, x>0

<u>Given</u>: The decay parameter is, \frac{1}{20}

<em>X</em> is defined as the distance people are willing to commute in miles.

  • The decay parameter is <em>m</em> = \frac{1}{20}.
  • The mean of the distribution is: \mu=\frac{1}{m}=\frac{1}{\frac{1}{20}}=20.
  • The standard deviation is: \sigma=\sqrt{variance}= \sqrt{\frac{1}{(m)^{2}} } =\frac{1}{m} =\frac{1}{\frac{1}{20}} =20

Compute the probability that a person is willing to commute more than 25 miles as follows:

P(X>25)=\int\limits^{\infty}_{25} {\frac{1}{20} e^{-\frac{1}{20}x}} \, dx \\=\frac{1}{20}|20e^{-\frac{1}{20}x}|^{\infty}_{25}\\=|e^{-\frac{1}{20}x}|^{\infty}_{25}\\=e^{-\frac{1}{20}\times25}\\=0.2865

Thus, the probability that a person is willing to commute more than 25 miles is 0.2865.

7 0
3 years ago
if a car traveling at 100 m/s must slam on the brakes to avoid hitting a raccoon and it takes 4 seconds for the car to slow down
rusak2 [61]

1.)

Velocity is in m/s, and acceleration is in m/s^2 like you said. Because of this, we can calculate this by dividing the speed by the time it took to get to that speed.

(20 meters/second) / 10 seconds = 2 meters/ second^2

2.)

Same thing with the first one.

(100 meters/second) / 4 seconds = 25 meters / seconds^2

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Illusion [34]

I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

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And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

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Next step is to plug in these values in the above formula. Therefore,

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x=\frac{8}{20} , \frac{30}{20}

So, x= \frac{2}{5} ,\frac{3}{2}

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Please help ASAP!!!! ​
katrin [286]

The answer is B i had this problem.

6 0
3 years ago
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