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3 years ago

Which of the following equations is of a line that is parallel to y = 3x + 2? *

Mathematics

1 answer:

Stells [14]3 years ago

8 0

Answer:

I don't see any answer choices, but read my explanation

Step-by-step explanation:

Any line with a slope of 3 would be parallel to y=3x+2.

For example,

y=3x+4

y=3x-1

y=3x

All of these lines are parallel to the original equation

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Simplify 2x^2+6x-7x+8-3x^2+1

Doss [256]

$(((((2*(x^2))+6x)-7x)+8)-3x^2)+1 \\ \\ ((((2x^2 + 6x) - 7x) + 8) - 3x^2) + 1 \\ \\ we \ would \ then \ (pull \ out) \ like \ terms. \\ \\ -x^2 - x + 9 = -1 * (x^2 + x - 9) \\ \\ \left[\begin{array}{ccc} -9 + 1 = -8 \\
 -3 + 3 = 0 \\
 -1 + 9 = 8 \\
\end{array}\right] \\ \\ Your \ answer: \boxed{\boxed{\bf{ -x^2 - x + 9
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I hope this helps you!

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3 years ago

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Limit question please?

Ksivusya [100]

The easiest way to evaluate the limit is to simply subsitute the value into the function

as x approaches -3
just subsitute -3 for x

(-3)³=(-3)(-3)(-3)=-27
answer is -27

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3 years ago

684,658 round to the nearest hundred thousand

OverLord2011 [107]

700,000 is the answer I believe

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3 years ago

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Solve the inequality and Graph the solution. -3x-4<19 PLEASE HELP!!!

Alisiya [41]

-3x-4<19
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2 years ago

8. If BD=BC, BD = 5x -26, BC = 2r + 1, and AC = 43, find AB.

charle [14.2K]

Answer:

Step-by-step explanation:

BD=DC

5x-26=2x+1

5x-2x=1+26

3x=27

x=9

BC=2x+1

=2*9+1

BC =19

so AB=AC-BC

AB=43-19

AB=24

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2 years ago