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Gnoma [55]
2 years ago
15

What is the difference between a linear function and a exponential function?

Mathematics
2 answers:
Kryger [21]2 years ago
8 0
When you graph a linear function, it is a straight  line ; When ou graph an exponential function, it is a curved line,
Natali [406]2 years ago
6 0
- Prove that linear functions change at the same rate over time. ... Linear functions take the form y = mx + b. An exponential function is in the form y = ax. It is easy to see the difference between a linear and exponential function on a graph.
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Please help with geometry
Bumek [7]
A. 19. You have to set them up equal to each other. So, 6x-2=4x+36. You then subtract the 4x from the 6x, and add 2 to 36. Which leaves you with 2x=38. Divide and you get 19! Hope this helps
4 0
2 years ago
To solve this question you have to use TAN COS SIN i give brainiest
ElenaW [278]

Answer:

  • 4.3

Step-by-step explanation:

<u>Use cosine:</u>

  • cos = adjacent / hypotenuse
  • cos ∠L = KL/JL
  • cos 21° = 4/x
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2 years ago
Read 2 more answers
What is the mean absolute deviation of the following set of data?<br> 4<br> 6<br> 6<br> 2.
MariettaO [177]

Answer:

To calculate the mean we need x and f both

7 0
3 years ago
6. An auto rental agency offers a rate of $60 per day plus $0.30 per mile. After a one-day rental, the bill was $93.60. How many
Nat2105 [25]

Answer:

112 miles

Step-by-step explanation:

93.60 - 60 = 33.60

33.60/0.30 = 112

7 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}&#10;r=\textit{rate of the plane}\\&#10;w=\textit{rate of the wind}\\&#10;\end{cases}&#10;\\\\&#10;&#10;\begin{array}{ccccllll}&#10;&distance&rate&time(hrs)\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;\textit{with wind}&630&r+w&1\frac{1}{2}\\&#10;\textit{against wind}&1120&r-w&4&#10;\end{array}&#10;

\bf thus  \begin{cases}&#10;630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}&#10;\\\\&#10;1120=(r-w)4\\&#10;--------------\\&#10;630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\&#10;420=r+w\implies \boxed{420-w}=r\\&#10;--------------\\&#10;thus\\&#10;--------------\\&#10;1120=(r-w)4\implies 1120=4r-4w&#10;\\\\&#10;1120=4(\boxed{420-w})-4w&#10;\end{cases}&#10;

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
2 years ago
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