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3 years ago

48. Climate A town's high temperature for a given

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

8 0

Answer: 65 ≤ x ≤ 88

Step-by-step explanation:

Let x denotes the temperature of the town for a given month.

Given : Climate A town's high temperature for a given month is 88°F and the low temperature is 65°F.

i.e. 65°F ≤ temperature in a given month ≤ 88°F

Replace temperature in a given month by x.

Thus the compound inequality to represent the range of temperatures for the given month :-

i.e. 65 ≤ x ≤ 88

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

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So by using zero product property we will get

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$t-7+7 = 0+7$

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So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

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When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

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$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

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I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST! A circle has a diameter AB, and its center is at (-3, 3). Point A is at (1/2,6)

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Using the mid-point concept, it is found that point B is located at coordinates (-6.5, 0).

<h3>What is the midpoint concept?</h3>

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More can be learned about the mid-point concept at brainly.com/question/10956693

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