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Natasha_Volkova [10]
3 years ago
14

The graph of a line passes through the two points (-2, 1) and (2, 1). What is the equation of the line written in general

Mathematics
1 answer:
Stells [14]3 years ago
6 0

Answer:

y - 1 = 0.

Step-by-step explanation:

First off, we need to find the slope between the two points. That would be (1 - 1) / (2 - -2) = 0 / 4 = 0.

So, we would have an equation y = mx + b, where m is the slope and b is the y-intercept. Since the slope is 0, we have y = 0x + b, or y = b.

If you examine the coordinates, y always equals 1. So, b = 1, and y = 1.

y = 1

y - 1 = 0.

Hope this helps!

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What is the solution to -3/4 x + 2 ≤ -7 ?
Dvinal [7]

Answer:

x ≥ 12

Step-by-step explanation:

Step 1: subtract 2 from both sides

Now you have; -3/4 x ≤ -9

Step 2: divide both sides by -3/4

Now you have x ≥ 12

(when dividing an inequality by a negative you have to flip the sign)

Therefore the answer is x ≥ 12

6 0
4 years ago
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Write an equation to match each graph:
babymother [125]

Answer:

Oblique downward straight line expression:

y=-x(x\geq 1)

Straight line expression:

y=-x+2(x\geq 1)

4 0
3 years ago
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Use the formula for the probability of two dependent events P(A and B) to derive the conditional probability formula for P(B | A
gregori [183]

The conditional probability formula for P(B | A) has been derived from two dependent events P(A and B).

<h3>What is said to be dependent events?</h3>

When the outcome from one event influences the outcome of the other, two events are referred to as dependent.

  • Dependent events in probability are generally real-life events that depend on another event to occur.
  • Sam, for example, did well on his math test because he prepared; the gym class used to have a football session even though Adam brought a football from home.
  • When you look at these examples, you will realize that one occurrence is dependent on the other.

Derivation of conditional probability from two dependent events P(A and B) is-

The probability multiplication rule is used to derive the conditional probability formula, P(A and B) = P(A)×P(B|A).

This rule is also known as P(AB). The Union symbol (∪) represents "and," as in event A occurring and event B occurring.

Step 1: Write the multiplication rule down:

           P(A and B) = P(A)*P(B|A)

Step 2: P(A) divides both sides of the equation:

           P(A and B) / P(A) = P(A)*P(B|A) / / P(A)

Step 3: On the right side of the equation, cancel P(A):

           P(A and B) / P(A) = P(B|A)

Step 4: Rewrite the equation as follows:

           P(B|A) = P(A and B) / P(A)

Therefore, P(B | A) conditional probability formula is compiled from two dependent events P (A and B).

To know more about the conditional probability, here

brainly.com/question/10739997

#SPJ4

8 0
2 years ago
In the picture below, what is the value of x?
lana [24]

Answer: 9

Step-by-step explanation:Because you have to loom at the answer

5 0
3 years ago
Please help with this problem
Andre45 [30]

Answer:

The length of the short side is 14.5 units, the length of the other short side is 18.5 units, and the length of the longest side is 23.5 units.

Step-by-step explanation:

The Pythagorean Theorem

<em> If a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse, then the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse. </em>

This relationship is represented by the formula:

                                                     a^2+b^2=c^2

Applying the Pythagorean Theorem  to find the lengths of the three sides we get:

(x)^2+(x+4)^2=(x+9)^2\\\\2x^2+8x+16=x^2+18x+81\\\\2x^2+8x-65=x^2+18x\\\\2x^2-10x-65=x^2\\\\x^2-10x-65=0

Solve with the quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-10,\:c=-65:\quad x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}\\\\x_{1}=\frac{-\left(-10\right)+ \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}=5+3\sqrt{10}\\\\x_{2}=\frac{-\left(-10\right)- \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}=5-3\sqrt{10}

Because a length can only be positive, the only solution is

x=5+3\sqrt{10}\approx 14.5

The length of the short side is 14.5, the length of the other short side is 14.5+4=18.5, and the length of the longest side is 14.5+9=23.5.

3 0
3 years ago
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