Answer:
1. two square root of ten
Step-by-step explanation:
Given expression is:
![\[\sqrt{5}* \sqrt{8}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%20%5Csqrt%7B8%7D%5C%5D)
Simplifying the expression:
![\[\sqrt{5}* \sqrt{4 \ast 2}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%20%5Csqrt%7B4%20%5Cast%202%7D%5C%5D)
= ![\[\sqrt{5}* \sqrt{4}*\sqrt{2}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%20%5Csqrt%7B4%7D%2A%5Csqrt%7B2%7D%5C%5D)
= ![\[\sqrt{5}* 2*\sqrt{2}\]](https://tex.z-dn.net/?f=%5C%5B%5Csqrt%7B5%7D%2A%202%2A%5Csqrt%7B2%7D%5C%5D)
= ![\[2 * \sqrt{5} * \sqrt{2}\]](https://tex.z-dn.net/?f=%5C%5B2%20%2A%20%5Csqrt%7B5%7D%20%2A%20%5Csqrt%7B2%7D%5C%5D)
= ![\[2 * \sqrt{10}\]](https://tex.z-dn.net/?f=%5C%5B2%20%2A%20%5Csqrt%7B10%7D%5C%5D)
So among the given options, option 1 is the correct one,namely, two square root of ten.
Answer:
1)D 2)C 3)A 4)B 5) A
Step-by-step explanation:
1) The area rectangle is 36x^2 -1
We know ,
A= l*b
=36x^2 -1
=(6x)^2 -1
=(6x+1) (6x-2)
This the value of l,b respectively.
So, Perimeter of rectangle is 2(l+b)
P=2(6x+1) + 2(6x-1)
=24x
2)The area of square is 4(x+5)^2
We know,
A=l^2
=4(x+5)^2
=4(x^2 + 10x + 25)
=(2x+10)^2
This is the value of l=2x+10.
So, Perimeter of square is 4l
P=4(2x+10)
=8x+40
3)The fully factorized form is
= -2x^2 + 10x +12
= -2x^2 + 12x -2x +12
= -2x(x-6) -2(x-6)
= -2(x-6) (x+1)
4)The fully factorized form is
=x^4 -81
=(x^2)^2 -9^2
=(x^2 + 9) (x^2 - 9)
=(x^2 + 9) (x^2 - 3^2)
=(x^2 + 9) (x + 3) (x - 3)
5)The fully factorized form is
= 5x^4 - 320
= 5(x^4 - 64)
= 5((x^2)^2 - 8^2)
= 5(x^2 + 8) (x^2-8)
Answer:
a < 2
Step-by-step explanation:
Did you mean " -3+-13y+10y^(2) " with the 2 as the exponent?
