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3 years ago

14

How do you find the angles on this special triangle?

2 answers:

Natalija [7]3 years ago

8 0

Well this is simple. First you have to know what type of formula your gonna be using. Which means you can’t use a squared+b squared=c squared.
So first you look for what angles you do have and that’s a 90 degree angle. Next you look for other givens like the two side are even. Now you know it’s a Isosceles triangle. So since we know we have 90 degree angel already and there can only be 90 left becasue it’s only 180 degrees in a triangle and 90+90 makes 180. You divid 90 by 2 and it gives you 45 and that’s the other two angles. Anther name for the triangle is 45,45,90 it’s called for special triangles when using square root.

Rasek [7]3 years ago

3 0

Answer:

it is isosceles triangle with an angle = 90. Two others angle are equal. sum of all angles in triangle is 180.

2x + 90=180 --> x=45

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A science museum has a spherical model of the earth with a diameter of 6.5 m. What is the volume of the model? Use 3.14 for and

natka813 [3]

radius = diameter/2

radius = 6.5/2 = $\frac{13}{4}$ m

<span>volume </span> $= \frac{4}{3}$ x $\pi$ x (radius)³

$= \frac{4}{3}$ x $\pi$ x $( \frac{13}{4})^3$

$= \frac{4}{3}$ x $\pi$ x $\frac{2197}{64}$

$= \frac{2197}{64}$

= 144 cubic meters

6 0

2 years ago

For what values of x does 25 Superscript x Baseline = 5 Superscript x squared minus 3?

umka2103 [35]

For this case we have the following equation:

$25^{x} = 5^{ x^2-3}$

Rewriting we have:

$5^{2 (x)} = 5^{ x^ 2-3}\\5^{ 2x} = 5^{ x^ 2-3}$

For expressions to be equal, exponents must be equal. So:

$2x = x ^ 2-3\\x ^ 2-2x-3 = 0$

To factor, we look for two numbers that, when multiplied, result in -3 and when added, result in -2. These numbers are -3 and 1.

$(x-3) (x + 1) = 0$

Thus, the roots are:

$x_ {1} = 3\\x_ {2} = - 1$

Answer:

$x_ {1} = 3\\x_ {2} = - 1$

8 0

3 years ago

What is 2/3 plus 4/9 equal

ss7ja [257]

2/3+4/9
denominator= 3*9=27
numerator = (18+12)= 30
therefore the answer is 30/27= 10/9

6 0

3 years ago

Read 2 more answers

Hi can you help me please?)

AlladinOne [14]

<em>*To solve for a specified variable, you need to isolate that variable onto one side.</em>

<h3>11.</h3>

Firstly, subtract 5r on both sides: $2p=q-5r$

Lastly, divide both sides by 2 and <u>your answer will be $p=\frac{1}{2}q-\frac{5}{2}r$ </u>

<h3>12.</h3>

First, subtract z on both sides of the equation: $-10-z=xy$

Next, divide both sides by y and <u>your answer will be $\frac{-10-z}{y}=x$ </u>

<h3>13.</h3>

Firstly, multiply both sides by b: $a=cb$

Next, divide both sides by c and <u>your answer will be $\frac{a}{c}=b$ </u>

5 0

3 years ago

On this corrdinate plane UVW has been transformed to form image U’ V’ W’.

egoroff_w [7]

Answer:

C

Step-by-step explanation:

Translate the image 2 units right and 1 unit up. Then rotate the image 180°.

Take the coordinate W, it is at (2, 4).

Translate 2 units right (add 2 to the x coordinate) and 1 up (add 1 to the y coordinate)

(2, 4) ------> (2 + 2, 4 + 1) -------> (4, 5)

A rotation of 180° (doesn't matter the direction) makes the coordinates their opposites. Positives become negatives and negatives become positive.

(4, 5) -------> (-4, -5)

8 0

1 year ago