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KIM [24]
3 years ago
7

An owner of a company spends $25 on office supplies. The owner is left with $20. Write an equation to find how much money he ori

ginally had.
Mathematics
2 answers:
Ad libitum [116K]3 years ago
8 0
Quick answer = [$45.00]
If he spent $25.00 and he is left with $20.00 then... 

  $25.00
+$20.00
= $45.00 

{Example}  Lets say you had $45 and you went to buy some fast food.. okay in the end your whole meal cost $25 so if your taking that $25 out of your $45 then you would be left with $20. So yeah...... 
aleksandr82 [10.1K]3 years ago
4 0
$20+$25=$45 therefore the owner of the company originally had $45
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Gabrielle sees a 30% discount on potted plants at the nursery. She chooses 3 potted plants whose regular prices are $3.59, $4.25
malfutka [58]

Using proportions, it is found that she will pay $8.28 in total after the discount.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Before tax, the total price is given by:

P = 3.59 + 4.25 + 3.99 = $11.83.

She gets a 30% discount, hence the proportion she pays is 70% of this amount, hence:

P = 0.7 x 11.83 = $8.28.

She will pay $8.28 in total after the discount.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

5 0
1 year ago
The senior class raised $1001 to buy new text books at $38.50 each. How many textbooks can they buy
Travka [436]
Well

divide 1001 ÷ 38.50!

which is 26!

the answer is 26.
7 0
3 years ago
Read 2 more answers
One side of triangle is half the longest side. The third side is
Keith_Richards [23]
Let S be the first side. 
Longest side is then 2S.
Third side is 2S-10.
Perimeter is sum of all three sides = S+2S+2S-10 = 75
=>
5S-10=75
5S=75+10=85
S=17

Therefore
S=17 is the first side. 
Longest side is then 2S=2*17=34.
Third side is 2S-10=2*17-10=24.
6 0
3 years ago
What is the solution to the inequality?
Zina [86]
10x+18<-2

10x+18 - 18 <-2 - 18

10x < 16

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X < -2
6 0
3 years ago
Read 2 more answers
What are the roots for the equation x^2-2x+37=0 in simplest a+bi form
Gnesinka [82]

\boxed{x_{1}=1+6i} \\ \\ \boxed{x_{2}=1-6i}

<h2>Explanation:</h2>

Since we need to write the roots in the simplest form:

a+bi

It is obvious that the roots are complex. To solve this, let's use the quadratic formula. For the Standard Equation:

ax^2+bx+c=0

The Quadratic Formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ Here: \\ \\ x^2-2x+37=0 \\ \\ So: \\ a=1 \\ b=-2 \\ c=37 \\ \\ x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(37)}}{2(1)} \\ \\ x=\frac{2\pm \sqrt{4-148}}{2} \\ \\ x=\frac{2\pm \sqrt{-144}}{2} x=\frac{2\pm \sqrt{-1}\sqrt{144}}{2} \\ \\ x=\frac{2\pm 12\sqrt{-1}}{2} \\ \\ but \ \sqrt{-1}=i \\ \\ Two \ solutions: \\ \\ x_{1}=\frac{2+12i}{2} \\ \\ \boxed{x_{1}=1+6i} \\ \\ x_{2}=\frac{2-12i}{2} \\ \\ \boxed{x_{2}=1-6i}

<h2>Lean more:</h2>

Real Roots: brainly.com/question/13740312#

#LearnWithBrainly

6 0
3 years ago
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