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Crank
3 years ago
12

Help me :))))) it’s a study guide.

Mathematics
1 answer:
Harman [31]3 years ago
6 0

Answer:B. Her mean, median and mode are equal.

Step-by-step explanation:

Mean = (sum of the outcomes)/(total number of outcomes)

Total number of rounds played is 7

The scores for the 7 rounds played are - 6, - 4, - 1 , +3 , - 2, -1, +4

Sum of the scores = - 6 - 4 - 1 + 3 - 2 -1 + 4 = -7

Mean = - 7/7 = - 1

The mode is the most occurring score. Looking at the scores, - 1 occurred twice, so the mode is - 1

The median is the middle score. We would determine it by rearranging the scores in increasing or decreasing order. It becomes

- 6, - 4, - 2, -1, -1, +3, +4

The median is -1

The true statement is

B. Her mean, median and mode are equal.

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Approximate the real zeros of f(x)= 2x^3 - 4x^2 - 3 to the nearest tenth.
Scrat [10]

Answer:

b.2.3

Step-by-step explanation:

f(x)= 2x^3 - 4x^2 - 3

see graph below

only x intercept is 2.287

6 0
3 years ago
164 is 55% of what number?<br><br> Please somebody help me
monitta
This is how you solve it; but first of all convert the percent into a decimal;55%= 0.55

0.55x = 164 (divide by 0.55 on both sides)
x = 164/0.55 
x = 298.18 (rounded to the nearest hundredth)
so 164 is 55% of 298.18(rounded)
8 0
3 years ago
Find the values of x and y in triangle ABCD
SVEN [57.7K]

Answer:

x and y = 66.5

Step-by-step explanation:

180-47=133

133/2=66.5

6 0
3 years ago
2&gt; -2-c. <br><br><br><br>how would I graph this?
REY [17]

Answer:

-4< c

Step-by-step explanation:

2> -2-c

Add 2 to each side

2+2> -2+2-c.

4 > -c

Divide each side by -1.  Remember that dividing by -1 will flip the inequality.

4/-1  < -c/-1

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6 0
3 years ago
According to the MIT Airline Data Project, American Airlines controlled 15.5% of the domestic market during a recent year. A ran
Naya [18.7K]

Answer:

0.0143

Step-by-step explanation:

In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.

We proceed as follows;

The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155

Let’s call this probability p

The probability that he/she isn’t on the flight, let’s call this q

q =1 - p= 0.845

Sample size, n = 155

P(X < A) = P(Z < (A - mean)/standard deviation)

Mean = np

= 125 x 0.155

= 19.375

Standard deviation = √npq

= √ (125 x 0.155x 0.845)

= 4.0462

P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)

= P(Z < (10.5 - 19.375)/4.0462)

= P(Z < -2.19)

= 0.0143

4 0
4 years ago
Read 2 more answers
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