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viktelen [127]
3 years ago
12

Please help!! Which values of a and b in the exponential function y=a*b^x would result in the following graph?

Mathematics
1 answer:
Masja [62]3 years ago
4 0

Answer: a=-3, b=2


Step-by-step explanation:

1. To solve this problem substitute the values of a and b into the function y=a*b^{x} and prove for the value x=0.

2. When x=0, b^{0}=1 and a*1=a; this means that the graph of the function should cut in the axis y=a, if this does not happen, the values of a and b are not the right ones.

3. Then, we conclude that the correct option is the Option A:

y=a*b^{x}

y=-3*2^{0}

y=-3

4. You can see that the function cut the y-axis at -3.


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Rounded to the nearest inch , what is the appoxiomate circumference of a circle with a diameter of 40 inches (Use pi = 3.14
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4 years ago
The table show the age in years of employees in a company
adelina 88 [10]

Answer:

A. 24 ≤ a < 26.

B. 22.5

Step-by-step explanation:

A. Determination of the modal class interval.

Mode is the class with the highest frequency.

From the table given above, the highest frequency is 8, therefore the class will the highest frequency is:

24 ≤ a < 26.

B. To obtain the mean, we must determine the class mark. This is illustrated below:

Class >>>>> class mark >>> frequency

18 – 19 >>>> 18.5 >>>>>>>>> 3

20 – 21 >>> 20.5 >>>>>>>> 2

22 – 23 >>> 22.5 >>>>>>>> 7

24 – 25 >>> 24.5 >>>>>>>> 8

26 >>>>>>>> 26 >>>>>>>>> 0

The mean is given by the summation of the product of the class mark and frequency divided by the total frequency. This is illustrated below:

Mean = [(18.5x3) + (20.5x2) + (22.5x7) + (24.5x8) + (26x0)] / (3+2+7+8+0)

Mean = (55.5 + 41 + 157.5 + 196 + 0)/20

Mean = 450/20

Mean = 22.5

Therefore, the mean age is 22.5

4 0
3 years ago
Read 2 more answers
Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 &lt; 2pi. Show work please!
yan [13]

Answer:

\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}

Step-by-step explanation:

You need 2 things in order to solve this equation:  a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

cos(2\theta)=1-2sin^2(\theta)

so we will make that replacement, getting everything in terms of sin:

sin(\theta)+1=1-2sin^2(\theta)

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

2sin^2(\theta)+sin(\theta)=0

We can factor out the sin(theta), since it's common in both terms:

sin(\theta)(2sin(\theta)+1)=0

Because of the Zero Product Property, either

sin(\theta)=0 or

2sin(\theta)+1=0

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi.  They are:

\theta=\frac{\pi}{2},\frac{3\pi}{2}

The next equation needs to first be solved for sin(theta):

2sin(\theta)+1=0 so

2sin(\theta)=-1 and

sin(\theta)=-\frac{1}{2}

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval.  They are:

\theta=\frac{2\pi}{3},\frac{4\pi}{3}

7 0
3 years ago
Help please.............
Sergeeva-Olga [200]

Answer:

6

Step-by-step explanation:

$68 per day and you want it to be >400

68x>400 -divide by 68 on both sides

is about 5.88 -round up to six because it wants a whole number and it needs  to be greater then 400

8 0
3 years ago
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