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2 years ago

Y = 2.5(5)x Pls helpppp

Mathematics

2 answers:

3241004551 [841]2 years ago

6 0

What it askin u to do

dexar [7]2 years ago

3 0

Rrrrrrrr1111111ddddddde

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At the start of the month, Jodie had sold 885 copies of her new book. At the end of the month, she had sold 1,364 copies of her

ozzi

Approximately $ 31419 profit is earned from selling books in entire month

Solution:

Given that Jodie had sold 885 copies of her new book

At the end of the month, she had sold 1,364 copies of her book

We have to determine the profit earned in the entire month

From given information,

Start of month sale = 885 copies

End of month sale = 1364 copies

Total copies of books sold = Start of month sold + end of month sold

Total copies of books sold = 885 + 1364 = 2249

Also given that each book profit is $ 13.97

Profit of 1 book = $ 13.97

Therefore for 2249 books, profit earned is given as:

Profit of 2249 books = $ 13.97 x 2249 = 31418.53

Therefore approximately $ 31419 profit is earned from selling books in entire month

5 0

3 years ago

Please helppppppp meeeeeeeeeeee

Paha777 [63]

Answer:

the answer is the third one

Step-by-step explanation:

3 0

3 years ago

I need an answer asap

allsm [11]

Answer:

yes

Step-by-step explanation:

8 0

3 years ago

I am totally stuck on this problem please help

Nonamiya [84]

V solid = π * $5^{2}$ * 13 / 3 + π * $5^{2}$ * 2 = 3.14 * 25 *13 / 3 + 3.14 * 50 = 340.16 + 157 = 497.16 ≈ 497.20 cubic centimeters;

3 0

3 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%

blondinia [14]

The trick is to exploit the difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

$(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2$

Whatever you do to the denominator, you have to do to the numerator too. So

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2$

Expand the numerator:

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}$

So we have

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2$

But √12 = √(3•4) = 2√3, so

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}$

7 0

3 years ago