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Mandarinka [93]
3 years ago
13

Point L has coordinates (3,-5). The coordinates of point L' after a reflection are (-3,-5). Without graphing, tell which axis po

int L was reflected across. Explain your answers.
Mathematics
1 answer:
klemol [59]3 years ago
4 0
The axis which the point is reflected is vertical because for two different x-values, there is one y-value. In this case, you can tell that the vertical axis is x=0, which is basically the y-axis itself. To find the reflection point, find the average between the two x values. (3+(-3))/2 0/2 0 This value 0 is the x-value of the vertical axis.
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30a^6-24a^2\\ GCF\; is \; 6a^2\\ \\ 30a^6-24a^2=6a^2(\frac{3a^6}{6a^2} -\frac{24a^2}{6a^2} )=6a^2(5a^4-4)\\ ---------------------\\ \\ 16a^5-20a^3\\ GCF \; is \; 4a^3\\ \\ 16a^5-20a^3=4a^3(\frac{16a^5}{4a^3} -\frac{20a^3}{4a^3})=4a^3(4a^2-5) \\ ---------------------\\ \\ 12a^3+8a\\ GCF \; is \; 4a\\ \\ 12a^3+8a=4a(\frac{12a^3}{4a}+\frac{8a}{4a})=4a(3a^2+2)\\   ---------------------\\ 24a^4+18\\GCF \; is \; 6\\\\24a^4+18=6(\frac{24a^4}{6} +\frac{18}{6})=6(4a^4+3) \\    ---------------------

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