Question

Whats the area of this triangle ​

Answer 1

(8÷2)^2+x^2=8^2
16+x^2=64
x^2=48
x=√48

(8×√48)÷2=27.71...

Answer:27.7in^2

Answer 2

Answer:

$\large\boxed{A=16\sqrt3\ in^2\approx27.7\ in^2}$

Step-by-step explanation:

It's the equilateral triangle.

The formula of an equilateral triangle wit sides a

$A=\dfrac{a^2\sqrt3}{4}$

We have a = 8in. Substitute:

$A=\dfrac{8^2\sqrt3}{4}=\dfrac{64\sqrt3}{4}=16\sqrt3\ in^2$