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krek1111 [17]
3 years ago
6

Help me please :33 :ppp

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

your speed is 8.1

Step-by-step explanation:

17.5-9.4=8.1

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Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),
amm1812

Answer:

Step-by-step explanation:

Approximate the integral \int\int\limits_R {f(x,y)} \, dA by dividing the region R with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i

Since all are equal squares, so \delta A_i=1 for every i

\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24

Thus, \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24

Evaluating the iterate integral \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.

Thus, \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24

7 0
3 years ago
If f(x)=3x+1 and g(x)=x^2-6 find (f-g)(x)
8090 [49]
Hi there!

• f(x) = 3x + 1
• g(x) = x² - 6

Then,
According to th' question :-

(f - g)(x) = f(x) - g(x)

= 3x + 1 - (x² - 6)

= 3x + 1 - x² + 6

= -x² + 3x + 7

Hence,
Option 2ⁿᵈ : -x² + 3x + 7 is Correct.

~ Hope it helps!
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3 years ago
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9.06. It cannot be any other number because it must be between 9.04 and 9.15 and no other number has a 6 (9.04, 9.05, 9.06, 9.07, 9.08, 9.09, 9.10, 9.11, 9.12, 9.13, 9.14, 9.15). 
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Len [333]
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3 years ago
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-1.2w=9//////.........................
finlep [7]

Answer:

this aint a question right?

Step-by-step explanation:

8 0
3 years ago
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