Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution?

What is the area and perimeter?

luda_lava [24]

Answer:

Perimeter: 26 units

Area: 24 units²

Step-by-step explanation:

12 + 9 + 5 = 26

A = 1/2BH

A = 1/2 12(4)

A = 1/2 48

A = 24

7 0

3 years ago

Read 2 more answers

Pete, Lulu and Liza are walking in the Boston downtown. Each time Pete takes 4

Rasek [7]

If Liza takes 120 steps, then the number of steps taken by Pete will be 72.

<h3>What are a ratio and a proportion?</h3>

A ratio is an ordered set of integers a and b expressed as a/b, with b never equaling 0. A percentage is a mathematical expression in which two things are equal.

Pete, Lulu, and Liza are walking in the Boston downtown. Each time Pete takes 4 steps, Lulu takes 3 steps. Each time Lulu takes 5 steps, Liza takes 4 steps.

Then the relation between is given as

4 Pete → 4 Lulu

5 Lulu → 4 Liza

Then we have

$\rm \dfrac{5}{3} \times 4 \ Pete \rightarrow \dfrac{5}{3} \ Lulu \rightarrow 4 \ Liza$

If Liza takes 120 steps, then the number of the step taken by Pete will be

$\rm \dfrac{5}{3} \times 4 \ Pete \rightarrow 4 \times 120 \\\\Pete \rightarrow 72$

More about the ratio and the proportion link is given below.

brainly.com/question/14335762

#SPJ1

7 0

1 year ago

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Pavlova-9 [17]

Answer:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

$p_v =P(t_{(15)}>1.507)=0.076$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X_{CTS}=2.35$ represent the mean for the sample CTS

$\bar X_{N}=1.83$ represent the mean for the sample Normal

$s_{CTS}=0.88$ represent the sample standard deviation for the sample of CTS

$s_{N}=0.54$ represent the sample standard deviation for the sample of Normal

$n_{CTS}=10$ sample size selected for the CTS

$n_{N}=7$ sample size selected for the Normal

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis: $\mu_{CTS} \leq \mu_{N}$

Alternative hypothesis: $\mu_{CTS} > \mu_{N}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{CTS}+n_{N}-2=10+7-2=15$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(15)}>1.507)=0.076$

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0

3 years ago

If a stadium has 15,000 seats sold at $10.00, $12.50, and $15.00 equally distributed in three sections, how much can be made if

ELEN [110]

If it is equally distrubuted in 3 sections then we would divide 15,000 by 3. Now we take one section which would cost $10.00 and multiply it by the 5,000 since we divided. We would do the same with all three and then add it together.

$10 * 5,000 = $50,000 section one can sell this much
$12.50 * 5,000 = $62,500 section two can sell this much
$15 * 5,000 = $75,000 section three can sell this much

If all the seats are sold than 50k + 62.5k + 75k = $187,500 can be made

3 0

3 years ago

Given: x - 5> -2.

Mice21 [21]

Answer: $\{x|x \exists \mathbb{R}, x > 3 \}$

Step-by-step explanation:

Adding 5 to both sides, we get <u>x > 3.</u>

7 0

2 years ago