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Sveta_85 [38]
3 years ago
15

Write 3 1/3 as an improper fraction

Mathematics
2 answers:
umka21 [38]3 years ago
7 0
10/3 because you time 3 and 3 then add 9 plus 1 equals 10 so it's 10/3
MArishka [77]3 years ago
3 0
<span> 3 1/3 as an improper fraction would be 10/3</span>
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Then the statement is true.

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Answer: \dfrac{3}{8}

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4 0
3 years ago
1. Amanda tells you that because a variable is in the denominator, the equation three over x plus one over three equals five ove
Hunter-Best [27]

Answer: x = 6

<u>Step-by-step explanation:</u>

\dfrac{3}{x}+\dfrac{1}{3}=\dfrac{5}{6}

(6x)\dfrac{3}{x}+(6x)\dfrac{1}{3}=(6x)\dfrac{5}{6}  <em>multiplied by common denominator</em>

18 + 2x = 5x

<u>       -2x</u>   <u>-2x</u>

18         = 3x

<u>÷3         </u>  <u>÷3 </u>

6          =  x

Since "x" is in the denominator, the restriction is that x ≠ 0.  If the solution was x = 0, then the solution would not be valid and would be eliminated as an answer.

Remember that "x" is just an unknown value.  It is possible to add two fractions together and have their sum be a fraction.

For example: \dfrac{1}{5} + \dfrac{2}{5} = \dfrac{3}{5} could be written as \dfrac{1}{5} + \dfrac{2}{x} = \dfrac{3}{5}.  When we solve it, we will get x = 5.

******************************************************************************************

Answer: Edward

<u>Step-by-step explanation:</u>

f(x)=\dfrac{(x-1)(x+2)(x+4)}{(x+1)(x-2)(x-4)}

The denominator cannot equal zero, so:

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Those x-values are the asymptotes, which is where the function is undefined.

4 0
4 years ago
Fill in the blank in the sentence below with the correct term.
VARVARA [1.3K]

Answer:

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3 years ago
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