19-20 = -1 u have to subtract left from tight <span />
Hello,
Assume x the smallest side.
y the third side
z the largest side
z=2x-4
y=10+x
x+y+z=86
==>x+(10+x)+(2x-4)=86
==>4x=86-10+4
==>x=20, y=30 and z=36
What you want is P(6∩1) or P(1∩6) or P(2∩5) or P(5∩2) or P(3∩4) or P(4∩3).
The events of rolling the dice are independent (i.e. they don't affect one another) so:
E.g.
P(6∩1) = P(6) * P(1)
P(2∩5) = P(2) * P(5)
The probability of getting a given number on a roll is 1/6 for both dice.
So:
P(6∩1) = 1/6 * 1/6 = 1/36
This is the same for any arrangement of numbers you could get from rolling two dice.
So, we can see that there are 6 arrangements of numbers that will give a sum of 7 and so that is 6 * 1/36 = 6/36 = 1/6
3t=7+5=12
3t=12
t=4
6t=6×4=24
The answer is 24
an aritmetic sequence increases by the same amount each time (if it decreases, then it increases by a negative number)
the common difference is the number that must be added to a term to get the next term
let's see if it increases by the same amount
-5 to -11 is increase of -6
-11 to -17 is increase of -6
-17 to -23 is increase of -6
-23 to -29 is increase of -6
so it appears to be aritmetic
common difference is -6
-29-6=-35
-35-6=-41
-41-6=-47
the next 3 terms are -35, -41, -47
