4 years ago

4x4

Mathematics

1 answer:

aivan3 [116]4 years ago

5 0

Answer:

60=2(20)+2x

x=10

Step-by-step explanation:

First, let's write some equations. I wrote 60=2(20)+2x, where x is the length of the room. To solve, first multiply 2 times 20 for 40 (60=40+2x). Then, I subtracted 40 from both sides (20=2x). Finally, I divided on both sides by 2 (10=x).

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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Pavel [41]

$\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Explanation:</h2>

Using the quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$