Determine which measures of center would be more appropriate to use for each of these variables

Mathematics

1 answer:

olga_2 [115]3 years ago

6 0

Answer:

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Step-by-step explanation:

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Round 2,212,682 to the nearest thousand

Artist 52 [7]

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3 years ago

How much should you put in an investment paying a simple interest rate of 5% if you needed $4000 in eighteen mont

Eddi Din [679]

now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P$