Question

A certain tennis player makes a successful first serve 6969​% of the time. Suppose the tennis player serves 9090 times in a match. ​a)​ What's the mean and standard deviation of the number of good first serves​ expected? ​b) Determine if you can use a normal model to approximate the distribution of the number of good first serves. ​c)​ What's the probability she makes at least 7272 first​ serves?

Answer 1

Answer:

a) 4.387

b) Yes, because np & npq are greater than 10.

c) = 0.017          

Step-by-step explanation:

Give data:

p = 0.69

n = 90

a) a

E(X) = np = 62.1

$SD(X) = \sqrt{(np(1-p))}$

          $=\sqrt{90\times 0.69(1- 0.69)}$

          = 4.387

b)

np = 62.1  

q = 1 - p  = 1 - 0.69 = 0.31

npq = 19.251

Yes, because np & npq are greater than 10.

c.

$P(X \geq 72 ) = P(X > 71.5)$ [continuity correction]

$= P(Z> \frac{((71.5-62.1)}{ 4.387})$

= P(Z> 2.14 )      

= 1 - P(Z<2.14)              

= 1 - 0.983   (using table)          

= 0.017