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Dmitrij [34]
3 years ago
6

Nadia and Sergio are saving money to buy bicycles. Nadia has $10 more than twice as many dollars as Sergio . If Sergio has x dol

lars, which expression represents how much Nadia has saved
Mathematics
2 answers:
KatRina [158]3 years ago
4 0
2x + 10
Please mark Brainliest if it helped!
ololo11 [35]3 years ago
3 0

The answer is 2x + 10.

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Step-by-step explanation:

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A shop sells floor tiles at Rs 48 per square meter. A
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Answer:

c. 528000

Step-by-step explanation:

The computation of the amount that need to be paid is shown below:

Let us assume the side of the square shaped hall be X meter s

So,

Perimeter = 4X

Now

4X = 400

X = 100m

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Area of the hall = 100 × 100 = 10000 sq. meter.

And,

The cost on total tiles is

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But, there is 10% damage has occurred that involved in the cost

So,

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Jen is writing a financial assets and liabilities which item doesn't belong out of these choices. stocks, taxes, mortgage, and r
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8 0
3 years ago
☆15 POINTS AND MARKED BRAINLIEST IF CORRECT☆<br>look at the image above to view the question!​
swat32

Answer:

3125 bacteria.

Step-by-step explanation:

We can write an exponential function to represent the situation.

We know that the current population is 100,000.

The population doubles each day.

The standard exponential function is given by:

P(t)=a(r)^t

Since our current population is 100,000, a = 100000.

Since our rate is doubling, r = 2.

So:

P(t)=100000(2)^t

We want to find the population five days ago.

So, we can say that t = -5. The negative represent the number of days that has passed.

Therefore:

\displaystyle P(-5)=100000(2)^{-5} = 100000 \Big( \frac{1}{32}\Big)  = 3125 \text{ bacteria}

However, we dealing within this context, we really can't have negative days. Although it works in this case, it can cause some confusion. So, let's write a function based on the original population.

We know that the bacterial population had been doubling for 5 days. Let A represent the initial population. So, our function is:

P(t)=A(2)^t

After 5 days, we reach the 100,000 population. So, when t = 5, P(t) = 100000:

100000=A(2)^5

And solving for A, we acquire:

\displaystyle A=\frac{100000}{2^5}=3125

So, our function in terms of the original day is:

P (t) = 3125 (2)^t

So, it becomes apparent that the initial population (or the population 5 days ago) is 3125 bacteria.

3 0
3 years ago
Read 2 more answers
Find the area of this trapezoid. Be sure to include the correct unit in your answer. Continue 13 cm 20 cm 8 cm 5 cm 0 0/0 08 cm
kodGreya [7K]

Given:

• Upper Base of trapezoid = 8 cm

,

• Lower base = 20 cm

,

• Length of one leg (also height) = 5 cm

,

• Length of other leg = 13 cm

Let's find the area of the trapezoid.

To find the area of the trapezoid, apply the formula:

A=\frac{a+b}{2}*h

Where:

A is the area

a is the length of upper base = 8 cm

b is the length of the lower base = 20 cm

h is the height = 5 cm

Plug in the values for a, b, and h to find the area, A:

\begin{gathered} A=\frac{8+20}{2}*5 \\  \\ A=\frac{28}{2}*5 \\  \\ A=14*5 \\  \\ A=70\text{ cm}^2 \end{gathered}

Therefore, the area of the trapezoid is 70 cm^2

8 0
1 year ago
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