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melomori [17]
3 years ago
7

a room with dimensions 10 ft by 5 ft require 400 tiles. how many tiles are needed for a room that measures 7 ft by 21 ft?

Mathematics
2 answers:
satela [25.4K]3 years ago
8 0

Answer:

1176

Step-by-step explanation:

A room with dimensions 10 ft by 5 ft has an area of 50 ft².

A room with dimension 7 ft by 21 ft has an area of 147 ft².

Writing a proportion:

400 tiles / 50 ft² = x / 147 ft²

x = 1176 tiles

mrs_skeptik [129]3 years ago
3 0

Answer:

1176

Step-by-step explanation:

A room with dimensions 10 ft by 5 ft require 400 tiles. There would be 1176 tiles needed for a room that measures 7 ft by 21 ft.

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Step-by-step explanation:

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3 years ago
Identify any solutions to the system given below.
alekssr [168]

Answer: The system of equations have many solutions and the correct options are A,B and D.

Explanation:

The given equations are,

2x+y=5     ..... (1)

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Simplify the second equation.

3y+6x=15

3(y+2x)=15

Divide both sides by 3.

2x+y=5

It is same as equation (1). Since equation (1) and (2) are same, therefore all the points lies on the line or which satisfies the equation are the solution of the given system of equations.

Test the points whether the point lies on the line or not.

Check for point A(6,-7).

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LHS and RHS are equal, therefore the point A is the solution of the system of equations.

Check for point B(2,1).

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LHS and RHS are equal, therefore the point B is the solution of the system of equations.

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Check for point D(-4,13).

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LHS and RHS are equal, therefore the point D is the solution of the system of equations.

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3 0
4 years ago
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Answer:

A =63.76512739 in^2

Step-by-step explanation:

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3 years ago
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