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miskamm [114]
3 years ago
12

Write the slope and y intercept of each equation:

Mathematics
1 answer:
vichka [17]3 years ago
7 0

Answer:

A) slope = 2, y-intercept = -6

B) slope = -4, y-intercept = 6

Step-by-step explanation:

A) y = 2x - 6

The equation for a line is y = mx + b, where <em>m</em> represents the slope, and <em>b</em> represents the y-intercept. So, to find the slope and y-intercept, all we have to do is look at the line's equation.

Here, the <em>m </em>is 2, so the slope is 2

The <em>b</em> is -6, so the y-intercept is -6

B) y = -4x + 6

Here, the <em>m</em> is -4, so the slope is -4

The <em>b </em>is 6, so the slope is 6

You would graph the equation y = 4x + 6 by plotting a point at the y-intercept of the line, which would be 6. Then, for every time you move one space to the right, you'd plot a point four spaces up to show the slope of four.

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ANSWER PLEASE LORD ANSWER
sesenic [268]

Answer:

< 2.11, 4.53 >, < -3.03, -1.75 >, <2.93 cos 108.26, 2.93 sin 108.26 >

Step-by-step explanation:

First, let's decompose Bruce's velocity along the x- and y- direction. Bruce is moving 5 m/s at 25 degrees east of north, so its angle with respect to the positive x-direction is actually 90 - 25 = 65 degrees. So its components are

b_x = (5 m/s) cos 65^{\circ} =2.11 m/s\\b_y = (5 m/s) sin 65^{\circ} =4.53 m/s

So, Bruce's vector is

< 2.11, 4.53 >

The current is moving 3.5 m/s at an angle 60 degrees west of south, which means an overall angle of 210 degrees, measured counterclockwise from the positive x-axis. So, the components of the current's velocity are

c_x = (3.5 m/s) cos 210^{\circ}=-3.03 m/s\\c_y = (3.5 m/s) sin 210^{\circ}=-1.75 m/s

So, the current's vector is

< -3.03, -1.75 >

Finally, we can add the components of the two vectors to find Bruce's actual velocity:

v_x = b_x + c_x = 2.11 + (-3.03)=-0.92 m/s\\v_y = b_y + c_y = 4.53+(-1.75)=2.78 m/s

So, Bruce's actual velocity is

< -0.92, 2.78 >

The magnitude is

v=\sqrt{(-0.92)^2+(2.78)^2}=2.93 m/s

And the direction is

\theta=180^{\circ} - tan^{-1} (\frac{v_y}{v_x})=180^{\circ} - tan^{-1}(\frac{2.78}{-0.92})=180^{\circ}-71.7^{\circ}=108.3^{\circ}

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3 years ago
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What is the property of 42x1=42
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Identity property of multiplication
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Assume that ∠A  is an acute angle. If sin A = 0.994, use a calculator to find the measure of ∠A to two decimal places.   The mea
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