d. both a relation and a function:
Given:
Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment.
x represents the number of assessments since he starts recording and y represents the scores in each assessment.
In order for a relation to be a function the association has to be unambiguous that means that for a given input only one output can exist.If an input can have two or more outputs then you cannot determine which is the correct output for that input.
In the given situation:
x is the input that is number of assessments since mark starts recording the scores so there is only one assessment no repeating.so there is only one output.
Hence the relation is a function.
Learn more about the function here:
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Answer:
<h2><u>
=</u>
<u>
57
/ 514 </u>
<u>
(Decimal: 0.110895)</u></h2>
Step-by-step explanation:
57
/ 514
<u>= 57
/ 514
</u>
<u>(Decimal: 0.110895)</u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
<u></u>
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<h2><u>
And if that is not what you are looking for here: </u></h2><h2><u>
</u></h2>
Rewrite the equation as
x
/14
= 5/
7
. x/
14
= 5/
7
Multiply both sides of the equation by
14.14 ⋅ x
/14
= 14
⋅
5
/7
Simplify both sides of the equation.
Tap for fewer steps...
Cancel the common factor of 14
.
Cancel the common factor.
14
⋅ x
/14
= 14
⋅
5
/7
Rewrite the expression.
x
=
14
⋅
5
/7
Simplify 14
⋅ 5/
7
.
Cancel the common factor of 7
.
Factor 7 out of 14
.
x
=
7
(
2
)
⋅
5/
7
Cancel the common factor.
x
=
7
⋅ 2
⋅ 5/
7
Rewrite the expression.
x =
2
⋅
5
Multiply 2 by 5
.
<u>x
=
10</u>
<h2>
Answer:</h2>
cos 28°cos 62°– sin 28°sin 62° = 0
<h2>
Step-by-step explanation:</h2>
From one of the trigonometric identities stated as follows;
<em>cos(A+B) = cosAcosB - sinAsinB -----------------(i)</em>
We can apply such identity to solve the given expression.
<em>Given:</em>
cos 28°cos 62°– sin 28°sin 62°
<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>
A = 28°
B = 62°
<em>∴ Substitute these values into equation (i) to have;</em>
<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>
<em />
<em>Solve the left hand side.</em>
<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>
⇒ 0 = <em>cos28°cos62° - sin28°sin62° (since cos 90° = 0)</em>
<em />
<em>Therefore, </em>
<em>cos28°cos62° - sin28°sin62° = 0</em>
<em />
<em />
