Step-by-step explanation:
The final grade is the average of the two semesters.
70 = ½ (60 + x)
x = 80
So Catherine needs a Semester 2 grade of 80%.
The average of RC3 and RC4 is ½ (62 + 53) = 57.5. This accounts for 90% of the Semester 2 grade. The other 10% is the Spring final.
80 = 0.90 (57.5) + 0.10 (x)
x = 282.5
Catherine would have to score 282.5% on the Spring final in order to pass.
Let the token profit be X.
For a win, the profit is 2 tokens.
For a loss, the profit is -3 tokens.
The probability of a win is
<span><span>212</span>+<span>212</span>+<span>212</span>=<span>612</span>=<span>12</span></span>
the probability of a loss is
<span><span>612</span>=<span>12</span></span>
Setting up a probability distribution variable gives:
<span>E(X)=(−3×<span>12</span>)+(2×<span>12</span>)=−1<span>12</span>+1=−<span>12</span> token</span><span>
Therefore, on average, the player would expect to lose a half a token per game.</span>
I believe the answer is 8384 and to the power or 4in
12-4=8 which means 12-8=4 which means now you have the difference of 4 and 8+4=12 which means now you have the sum of 12
Step-by-step explanation:
x-3y=3y-3y
x-3y=0
hope this helps
