The least (or lowest) common denominator of 3, 16 and 8 is 16. That already points us to answer A.
Checking for each fraction:
1/2 * 8/8 = 8/16
3/16 * 1/1 = 3/16
7/8 * 2/2 = 14/16
Yep. Answer A.
Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
Not sure about remainder theorem but I'm sure that the last terms should all multiply tho the last term
see the expanded form is -45
so the last terms of each binomial should multiply to -45
3 times -5 times ?=-45
-15 times ?=-45
divide by -15
?=3
the question mark is 3
let the length of each shorter side be x
length of longer side= x+14
2(x+14) + 2x = 48
2x + 28 + 2x = 48
4x + 28 = 48
4x = 48-28
4x = 20
x = 5
shorter side = 5cm
<u>ANSWER</u>

<u>EXPLANATION</u>
The Cartesian equation is

We substitute


and

This implies that

Let us evaluate the exponents to get:

Factor the RHS to get:

Divide through by r²

Apply the double angle identity

The polar equation then becomes:
