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Sauron [17]
3 years ago
14

Solve 2(5x + 6) < x - 15 + 9x.​

Mathematics
1 answer:
ipn [44]3 years ago
3 0

Answer:

Hope that was helpful for you! Good luck.

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Bingel [31]

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Angle QPM and Angle LMP are alternate interior I'm pretty sure, so I think B or  second choice.

7 0
3 years ago
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Find measure dbc <br> 19<br> 22<br> 23<br> 161 <br> HELP !!!
uysha [10]
∠DBC = 19° since the two angles have to add up to 180, if x = 23, then 23 -4 = 19 for the right, and 7 x 23 = 161, and 161 + 19 = 180.
4 0
3 years ago
What is the first step when graphing the equation <br> y=-4x+1
Lady bird [3.3K]
The first step would be to plot the y-intercept, which in this case would be 1.
5 0
2 years ago
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What times what equals 30 but add to get 40?
musickatia [10]
Lets call those two unknown numbers a, b and write the info in the problem as equations:
a*b = 30
a + b = 40
lets solve for a in the second equation and substitute in the first:
<span>a + b = 40
</span>a = 40 - b
therefore:
<span>a*b = 30
</span>(40 - b)b = 30
40b - b^2 = 30
b^2 - 40b + 30 = 0
if we apply the general quadratic equation to solve we have:
b = (40 +- √(1600 - 120))/2
b = (40 +- √(1480<span>))/2
</span>b = (40 +- 38.47)/2
There are two solutions:
<span>b1 = (40 + 38.47)/2
</span><span>b1 = 39.24
b2 = (40 - 38.47)/2
</span>b2 = 0.765
lets use the second solution <span>b2 = 0.765, and substitute in the first equation to find a:
</span><span>a*b = 30
</span>a*0.765 = 30
a = 30/0.765
a = 39.216
so the numbers are 39.216 and 0.765
5 0
3 years ago
Read 2 more answers
Twenty-eight athletes participate in a 100-meter race. The time of each athlete is measured during the qualification round. The
andriy [413]

The average time of the 20 athletes who did not qualify for the final is 11.2 seconds .

<u>Step-by-step explanation:</u>

Here we have , Twenty-eight athletes participate in a 100-meter race. The time of each athlete is measured during the qualification round. The average time is 11 seconds. The 8 athletes with the fastest time qualified for the final. The average time of these 8 athletes is 10.5 seconds. Let's have equations for this:

\frac{x_1+x_2+.....+x_2_8}{28} = 11 where x_1, x_2, ....., x_2_8 are athletes

⇒ x_1 + x_2 + .. + x_2_8 = 11(28)= 308

⇒ (x_1 + x_2 + .. + x_8 )+ (x_9+x_1_0+...+x_2_8) = 308

⇒ (\frac{x_1 + x_2 + .. + x_8}{8}  )(8)+ (\frac{x_9+x_1_0+...+x_2_8}{20} )(20) = 308

⇒ 10.5(8)+m(20) = 308 , where m is average time of the 20 athletes who did not qualify for the final.

⇒ 84+m(20) = 308

⇒ 20m= 224

⇒ m=11.2

∴ The average time of the 20 athletes who did not qualify for the final is 11.2 seconds .

8 0
3 years ago
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