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bogdanovich [222]
3 years ago
8

Convert decimal 7.79 miles into mixed number milesnow

Mathematics
1 answer:
Kryger [21]3 years ago
8 0
7 and 79/100 miles that is the answer
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Explain how the Quotient of Powers was used to simplify this expression. 2 to the fifth power, over 8 = 22 By finding the quotie
astraxan [27]

Answer:

 we can do it by simplifying 8 to 2^3 to make both powers base two, and subtracting the exponents.

Step-by-step explanation:

We have been given the expression  \frac{2^5}{8}=2^2

8 can be rewritten as 2^3

Hence, the given expression becomes

\frac{2^5}{2^3}=2^2

After subtracting the exponents on left hand side of the equation we get:

2^2=2^2

we can do it by simplifying 8 to 2^3 to make both powers base two, and subtracting the exponents.

6 0
3 years ago
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Find the area of the figure shown below and type your result in the empty box.<br><br><br>​
lianna [129]

Answer:

did u forget to add the actual question

Step-by-step explanation:

5 0
2 years ago
Which ordered pair is NOT a solution of y = 5x - 4? a. (2, 6) b. (0, -4) c. (-1, -9) d. (1, 0)
kipiarov [429]

Answer: the answer is (D) you might want to use a table to figures it out

5 0
3 years ago
Solve the system using an equivalent system
DerKrebs [107]
Add y to both sides in 1st equation
-2x=y
sub -2x for y in2nd equation
3x-(-2x)=10
3x+2x=10
5x=10
divide 5
x=2

sub back
-2x=y
-2(2)=y
-4=y

(x,y)
(2,-4)
C is ans
8 0
3 years ago
Find the nth maclaurin polynomial for the function. f(x) = 5x − 5 x + 1 , n = 4 p4(x)
zysi [14]
Assuming the function is f(x)=\dfrac{5x-5}{x+1}, and not 5x-5x+1=1 which would be its own Maclaurin polynomial right away.

\dfrac{5x-5}{x+1}=\dfrac{5(x-1)}{x+1}=\dfrac{5(x+1-2)}{x+1}=5-\dfrac{10}{1+x}

Recall the geometric power series,

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

where |x|. Replace x\mapsto-x and we have

\displaystyle\sum_{n=0}^\infty (-x)^n=\frac1{1+x}

and so

f(x)=5-10\displaystyle\sum_{n=0}^\infty(-x)^n

We want the 4th degree polynomial, so

p_4(x)=-5+10x-10x^2+10x^3-10x^4
7 0
3 years ago
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