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3 years ago

Evaluate the arise tic series described: 12. 0,= 300, n = 25 (please help)

Mathematics

1 answer:

Tcecarenko [31]3 years ago

5 0

Go back to soccer tuve

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Find the sum. Long gone out of my mind

vazorg [7]

$4r {}^{3} s - rs + 7r {}^{3} s + 8rs - 3 + 8rs + 6 \\ add \: \: terms \: \: of \: \: same \: \: variables \\ 11r {}^{3} s + 15rs + 3$

<h2>Answer: d</h2>

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2 years ago

Cameron makes a blueprint for his game room to decide how to set up the room. He places the table in the center of the sketches

Anestetic [448]

$\sqrt{5\\$ is the correct answer. you use the Pythagorean Theorem with 2 as a and 1 as b. So the equation is $c^{2}$ = $2^{2}$ + $1^{2}$ .

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3 years ago

What is the domain for y=2x

Snowcat [4.5K]

Answer:

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4 years ago

Using the numbers 5, 8, and 24, create a problem using no more than four operations (adding, subtracting, multiplication, divisi

Alik [6]

The given three numbers are 5,8,24.

We have to use four operations (Adding, Subtracting,multiplication, division, square, square root, cube, cube root) out of these operation to make the result an irrational number.

$1. \sqrt{\frac{24}{8}} + 5=\sqrt{3}+5,\\\\2. \sqrt{\frac{24}{8}} - 5=\sqrt{3} -5 \\\\ 3.\sqrt{\frac{24 \times 5}{8}}=\sqrt{15} \\\\ 4. (5 \times 8 \times 24)^\frac{1}{3}$

There are many more examples that you can write.

Keep in mind

1. Sum of Rational and irrational is always irrational.

2. Difference of rational and irrational is always irrational.

As none of the 5,8,24 is a perfect square , nor addition of any two results in a perfect square, so square root of their addition or subtraction or multiplication results in an irrational number.

Similarly ,apart from 8, none of 5,24 is a perfect cube.So if you add or subtract any number from 8 and take their cube root or square root ,results in an irrational number.

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3 years ago

Read 2 more answers

Point M is the midpoint of PQ. The coordinates of P and M are given below.

Zepler [3.9K]

The coordinates of Q are (-1,6)

Further Explanation:

Given points are:

$(x_m, y_m) = (5, -2)\\(x_p,y_p) = (11, -10)$

The formula for mid-pint is:

$(x_m, y_m) = (\frac{x_p+x_q}{2} , \frac{y_p+y_q}{2})\\From\ this\ we\ get\\x_m = \frac{x_p+x_q}{2}\\Putting\ values\\5 =\frac{11+x_q}{2}\\5*2 = 11+x_q\\10 = 11+x_q\\10-11 = x_q\\x_q = -1\\AND\\y_m = \frac{y_p+y_q}{2}\\-2 = \frac{-10+y_q}{2}\\-2*2 = -10+y_q\\-4 = -10+y_q\\-4+10 = y_q\\y_q = 6$

The coordinates of Q are (-1,6)

Keywords: Coordinate geometry, mid-point

Learn more about mid-point at:

#LearnwithBrainly

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3 years ago